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3 years ago

HELP!!!!! what 2 numbers can you multiply to get -6 and then add to get 5

2 answers:

8 0

The numbers would be 1 and 6 you need to put the positive on the 6 and the negative on the 1 to get positive 5 when adding and -6 when multiplying

Hope this helps

Ulleksa [173]3 years ago

4 0

(6)x(-1)=(-6) and (6)+(-1) (<<< or 6-1)=(5)

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Answer:

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In the diagram below, R is located at (24,0), N is located at (12,18), T is located at (12,6), and E is located at (18,15). Assu

julsineya [31]

The midpoint of a segment divides the segment into equal halves

The coordinates of K are: $\mathbf{K = (12,12)}$
The coordinates of I are: $\mathbf{I = (24,24)}$
The coordinates of B are: $\mathbf{B = ( 30,33 )}$

The given parameters are:

$\mathbf{R =(24,0)}$

$\mathbf{N =(12,18)}$

$\mathbf{T =(12,6)}$

$\mathbf{E =(18,15)}$

K is the midpoint of N and T.

So, we have:

$\mathbf{K = (\frac{N_x + T_x}{2},\frac{N_y + T_y}{2})}$

This gives

$\mathbf{K = (\frac{12 + 12}{2},\frac{18+ 6}{2})}$

$\mathbf{K = (12,12)}$

E is the midpoint of T and I.

So, we have:

$\mathbf{E = (\frac{I_x + T_x}{2},\frac{I_y + T_y}{2})}$

This gives

$\mathbf{(18,15) = (\frac{I_x + 12}{2},\frac{I_y+ 6}{2})}$

Multiply through by 2

$\mathbf{(36,30) = (I_x + 12,I_y+ 6)}$

By comparison

$\mathbf{I_x + 12 = 36.\ I_y + 6 =30}$

So, we have:

$\mathbf{I_x= 24.\ I_y =24}$

Hence, the coordinates of I are:

$\mathbf{I = (24,24)}$

I is the midpoint of E and B.

So, we have:

$\mathbf{I = (\frac{E_x + B_x}{2},\frac{E_y + B_y}{2})}$

This gives

$\mathbf{(24,24) = (\frac{18 + B_x}{2},\frac{15 + B_y}{2})}$

Multiply through by 2

$\mathbf{(48,48) = (18 + B_x,15 + B_y)}$

By comparison

$\mathbf{18 + B_x = 48,\ 15 + B_y = 48 }$

So, we have:

$\mathbf{B_x = 30,\ B_y = 33 }$

Hence, the coordinates of B are:

$\mathbf{B = ( 30,33 )}$