the denominator cannot be zero, because the division by zero is not defined, therefore:
![\begin{gathered} x^2-9=0 \\ \text{Solving for x:} \\ x^2=9 \\ \sqrt[]{x^2}=\sqrt[]{9} \\ x=\pm3 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20x%5E2-9%3D0%20%5C%5C%20%5Ctext%7BSolving%20for%20x%3A%7D%20%5C%5C%20x%5E2%3D9%20%5C%5C%20%5Csqrt%5B%5D%7Bx%5E2%7D%3D%5Csqrt%5B%5D%7B9%7D%20%5C%5C%20x%3D%5Cpm3%20%5Cend%7Bgathered%7D)
Therefore the domain of (f o g)(x) is:
a^2+a-ab+3ab^2-b^2 I hope this helps
Answer:
02:3 and 12:18
Step-by-step explanation:
A proportion is formed when the larger ratio can be simplified to equal the smaller ratio:
#1
02:3 and 4:12
Reducing the larger ratio: 4:12=1:3
Hence, not a proportion.
#2
02:3 and 6:12
Reducing the larger ratio: 6:12=1:2
Hence, not a proportion.
#3
02:3 and 12:18
Reducing the larger ratio: 12:18=2:3
Hence, they form a proportion.
#4
02:3 and 12:18
Reducing the larger ratio: 12:36=1:3
Hence, not a proportion.
<span>9.5 gallons 171 miles
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9.5 gallons x miles
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x = 171(9.5)/247 =
</span>
please___________________
