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Delicious77 [7]
2 years ago
11

A city water district wants to encourage local businesses and homeowners to landscape with drought-tolerant plants. After disapp

ointing results from a publicity campaign, the water district decides to subsidize local plant nurseries so they can offer the plants at a lower price.
Suppose the graph shows the supply and demand curves for a drought-tolerant plant, such as purple sage. Drag the appropriate curve to show the impact of the water district subsidy.

Chemistry
1 answer:
tino4ka555 [31]2 years ago
3 0

Answer:

the complete question is found in the attachment

Explanation:

the complete explanation is found in the attachment

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Write an equation that shows the formation of a chromium(ii) ion from a neutral chromium atom.
daser333 [38]
The   equation  that  shows  the  formation  of  chromium (ii) ion  from  neutral  chromium  atom  is  as  follow
Cr ---> cr^2+   +  2e-
Cr^2+ is  the  chromium  ion   with  oxidation  state  of  two  which  is  one  of  the  common  ion  of  chromium.  Other  common  ion   of  chromium  include  chromium  of  oxidation  state  6  and  3

8 0
3 years ago
Read 2 more answers
I went for a walk the other day. I went four blocks east, then seven blocks south, then one block west and finally
nalin [4]

Answer:

a) distance is 4+7+1+8=20 blocks

b) displacement is 10 blocks

Explanation:

find displacement: x and y

x axis displacement = 4-1 = 3 blocks

y axis displacement = -7+8= 1 block

displacement = the square root of 3^2 + 1^2

= 9+1 = 10 blocks.

You can find the angle of displacement with respect to the initial position using trig identities, if you wish.

4 0
2 years ago
How many grams of water can be produced from 4.6 grams of Hydrogen and 7.3 grams of Oxygen?
12345 [234]

Answer:

The answer to your question is 8.21 g of H₂O

Explanation:

Data

mas of water = ?

mass of hydrogen = 4.6 g

mass of oxygen = 7.3 g

Balanced chemical reaction

                   2H₂  +  O₂  ⇒   2H₂O

Process

1.- Calculate the atomic mass of the reactants

Hydrogen = 4 x 1 = 4 g

Oxygen = 16 x 2 = 32 g

2.- Calculate the limiting reactant

Theoretical yield = H₂/O₂ = 4 / 32 = 0.125

Experimental yield = H₂/ O₂ = 4.6/7.3 = 0.630

From the results, we conclude that the limiting reactant is Oxygen because the experimental yield was higher than the theoretical yield.

3.- Calculate the mass of water

                   32 g of O₂ ---------------- 36 g of water

                   7.3 g of O₂ ---------------   x

                          x = (7.3 x 36) / 32

                          x = 262.8 / 32

                          x = 8.21 g of H₂O

4 0
3 years ago
Calculate the theoretical yield of alum expected from 0.9875 g of aluminum foil. assume the aluminum is the limiting reactant.
skelet666 [1.2K]

Answer: 17.34 grams of alum will be produced if 0.9875 g of Aluminium foil was used.

Explanation: Reaction to form alum from Aluminium is given as:

2Al(s)+2KOH(aq.)+2H_2O(l)+4H_2SO_4(aq.)\rightarrow 2KAl(SO_4)_2(s).12H_2O(l)+3H_2(g)

We are given Aluminium to be the limiting reactant, so the formation of alum will be dependent on Aluminium because it limits the formation of product.

By stoichiometry,

2 moles of Al is producing 2 moles of Alum

Mass of 2 moles of Aluminium = (2 × 27)g/mol = 54 g/mol

Mass of 2 moles of alum = (2 × 474)g/mol = 948 g/mol

54 g/mol of aluminium will produce 948 g/mol of alum, so

\text{0.9875 grams of aluminium will produce}=\frac{948g/mol}{54g/mol}\times 0.9875g

Amount of Alum produced = 17.34 grams

Theoretical yield of alum = 17.34 grams.

5 0
3 years ago
What is the molarity of 5.74 liters of solution made with 246 grams of iron (III) chloride (FeCl3)? Answer with 3 SDs.
geniusboy [140]

Answer:

0.264 mol/L

Explanation:

Data obtained from the question includes:

Volume = 5.74L

Mass of FeCl3 = 246 g

Molarity =?

Next, we shall determine the number of mole in 246g of FeCl3.

This is illustrated below:

Mass of FeCl3 = 246g

Molar mass of FeCl3 = 56 + (35.5x3) = 162.5g/mol

Number of mole of FeCl3 =..?

Mole = Mass /Molar Mass

Number of mole of FeCl3 = 246/162.5

Number of mole of FeCl3 = 1.514 mol

Now, we can obtain the molarity of the solution as follow:

Molarity = mole /Volume

Volume = 5.74L

Mole of FeCl3 = 1.514 mol

Molarity = 1.514/5.74

Molarity = 0.264 mol/L

5 0
3 years ago
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