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yan [13]
3 years ago
13

5. Which phase of matter can be defined as:

Chemistry
1 answer:
-Dominant- [34]3 years ago
7 0

Answer:

I think it A not sure if I get it wrong sorry I need points.

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Why is a molecule of CO2 nonpolar even though the bonds between the carbon atom and the oxygen atoms are polar?
schepotkina [342]
The correct answer is option 1. Carbon dioxide is nonpolar because the shape of the molecule  is symmetrical. It is a linear molecule where the oxygen atoms are symmetrical on each end. CO2 molecule do not have a region of unequal sharing.
7 0
3 years ago
Makers faire ideas llll
muminat

Answer:

ummm what is that give me more detail please

6 0
3 years ago
how much potassium bromide, in grams, should be added to water to prepare 0.50 of solution with molarity of 0.125M?
Flura [38]
Volume = 0.50 L

Molar mass  KBr = 119.002 g/mol

Molarity = 0.125 M

Mass ( KBr) = ?

 mass = molarity * molar mass * volume

mass = 0.125 * 119.002 * 0.50

mass = 7.437625 g of KBr

hope this helps!
5 0
3 years ago
Which of the following is true about a carbonated soft drink?. . The carbon dioxide is the solvent, and water is the solute.. .
V125BC [204]

Answer:

The water is the solvent and the Carbon Dioxide is the Solute

Explanation:

The Carbon Dioxide is being dissolved into the Water. Solute is what is being dissolved, Solvent is what is doing the dissolving

7 0
3 years ago
The total volume of seawater is 1.5 x 10²¹ L. Seawater contains approximately 3.5% sodium chloride by mass. At that high of a co
garri49 [273]

Answer:

There are 5.408\times 10^{22} grams contained in all the seawater in the world.

Explanation:

At first let is determinate the total mass of seawater (m_{sw}), measured in grams, in the world by definition of density and considering that mass is distributed uniformly:

m_{sw} = \rho_{sw}\cdot V_{sw}

Where:

\rho_{sw} - Density of seawater, measured in grams per liters.

V_{sw} - Volume of seawater, measured in liters.

If V_{sw} = 1.5\times 10^{21}\,L and \rho_{sw} = 1030\,\frac{g}{L}, then:

m_{sw}=\left(1030\,\frac{g}{L} \right)\cdot (1.5\times 10^{21}\,L)

m_{sw} = 1.545\times 10^{24}\,g

The total mass of sodium chloride is determined by the following ratio:

r = \frac{m_{NaCl}}{m_{sw}}

m_{NaCl} = r\cdot m_{sw}

Given that m_{sw} = 1.545\times 10^{24}\,g and r = 0.035, the total mass of sodium chloride in all the seawater in the world is:

m_{NaCl} = 0.035\cdot (1.545\times 10^{24}\,g)

m_{NaCl} = 5.408\times 10^{22}\,g

There are 5.408\times 10^{22} grams contained in all the seawater in the world.

8 0
4 years ago
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