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Tcecarenko [31]
3 years ago
8

When did humans first learn that earth is not the center of the universe? around the time that early humans acquired language wi

thin the past 500 years about 2000 years ago we haven't; there is still considerable scientific debate about whether earth is the center of the universe?
Physics
1 answer:
lubasha [3.4K]3 years ago
8 0
The question was settled roughly 500 years ago. There's no longer any scientific debate on the matter.
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While driving on the highway, you have a tire blowout. after you have slowed down and regained control, you should?
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When a person has experienced a tire blow out, there are steps to follow in order to prevent harm to others and self. After following the required and helpful steps after a tire blow out, slowed down and regain control, it is best that the person should head to a stop road or at the safe side of the lane where they won't be a bother to the road or to people driving in the high way. After pulling over to the side, it is advisable to turn on the emergency flashers of the car. This will set as a signal that you are in need of help or had gone through a problem.
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4 years ago
2. What is a mirror? How does it work?​
Murljashka [212]

Answer:

a mirror is a glass which reflects the light falls on it ok

Explanation:

just put a light and see ok

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3 years ago
A long, thin rod parallel to the y-axis is located at x = - 1 cm and carries a uniform positive charge density λ = 1 nC/m . A se
zheka24 [161]

Answer:

The electric field at origin is 3600 N/C

Solution:

As per the question:

Charge density of rod 1, \lambda = 1\ nC = 1\times 10^{- 9}\ C

Charge density of rod 2, \lambda = - 1\ nC = - 1\times 10^{- 9}\ C

Now,

To calculate the electric field at origin:

We know that the electric field due to a long rod is given by:

\vec{E} = \frac{\lambda }{2\pi \epsilon_{o}{R}

Also,

\vec{E} = \frac{2K\lambda }{R}                  (1)

where

K = electrostatic constant = \frac{1}{4\pi \epsilon_{o} R}

R = Distance

\lambda = linear charge density

Now,

In case, the charge is positive, the electric field is away from the rod and towards it if the charge is negative.

At x = - 1 cm = - 0.01 m:

Using eqn (1):

\vec{E} = \frac{2\times 9\times 10^{9}\times 1\times 10^{- 9}}{0.01} = 1800\ N/C

\vec{E} = 1800\ N/C     (towards)

Now, at x = 1 cm = 0.01 m :

Using eqn (1):

\vec{E'} = \frac{2\times 9\times 10^{9}\times - 1\times 10^{- 9}}{0.01} = - 1800\ N/C

\vec{E'} = 1800\ N/C     (towards)

Now, the total field at the origin is the sum of both the fields:

\vec{E_{net}} = 1800 + 1800 = 3600\ N/C

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3 years ago
Which contribution did Kepler make to viewing the solar system?
amm1812
He proposed the sun-centered model of the solar system.
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The numbers of times you do lift without resting during a muscle training workout is called
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1. Improves health
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