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oee [108]
3 years ago
14

Is a baseball and cannon are dropped from the same height at the same time, which ball will hit the ground first?

Physics
2 answers:
lara31 [8.8K]3 years ago
8 0
If you include the effects of falling through air, then you have to know the
shape, size, weight, and surface texture of the objects.  You also have to
know the height from which they're dropped, and the temperature, pressure,
and humidity of the air.  All these things make a difference in how they fall.

If you ignore the effects of falling through air, like build a giant metal tank
and pump all the air out of it, and ONLY talk about the effects of gravity, then
ALL OBJECTS accelerate at the same rate.  If you drop two things from the
same height at the same time, then they both hit the ground at the same time,
traveling at the same speed, no matter what they are.  They could be a piece of
tissue and a car ! 

There are several museums where they have a big glass pipe that you can
see through, and they pump the air out of the pipe and drop a feather and a
bowling ball from the top inside at the same time, and they both reach the
bottom together.   

If gravity is the only force on an object, then all objects fall at the same rate.
hodyreva [135]3 years ago
7 0
Depends on the height. If they are dropped at a height which is high enough for them to reach terminal velocity, they will hit the ground at the same time. However, if they are dropped from a lower height, say, an average rooftop, the cannon will hit the ground first because it has the greater mass
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If you have 240.0 mL of water at 25.00 °C and add 100.0 mL of water at 95.00 °C, what is the final temperature of the mixture? U
Rus_ich [418]

<u>Answer:</u> The final temperature of the mixture is 45.6°C

<u>Explanation:</u>

To calculate the mass of water, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

Density of water = 1 g/mL

  • <u>When volume is 240.0 mL</u>

Putting values in above equation, we get:

1g/mL=\frac{\text{Mass of water}}{240.0mL}\\\\\text{Mass of water}=(1g/mL\times 240.0mL)=240g

  • <u>When volume is 100.0 mL</u>

Putting values in above equation, we get:

1g/mL=\frac{\text{Mass of water}}{100.0mL}\\\\\text{Mass of water}=(1g/mL\times 100.0mL)=100g

When two water solutions at different temperature are mixed, the amount of heat released by water present at higher temperature will be equal to the amount of heat absorbed by water present at lower temperature..

Heat_{\text{absorbed}}=Heat_{\text{released}}

The equation used to calculate heat released or absorbed follows:

Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})

m_1\times c\times (T_{final}-T_1)=-[m_2\times c\times (T_{final}-T_2)]       ......(1)

where,

q = heat absorbed or released

m_1 = mass of water solution 1 = 240 g

m_2 = mass of water solution 2 = 100 g

T_{final} = final temperature = ?°C

T_1 = initial temperature of water solution 1 = 25°C

T_2 = initial temperature of water solution 2 = 95°C

c = specific heat of water= 4.186 J/g°C

Putting values in equation 1, we get:

240\times 4.186\times (T_{final}-25)=-[100\times 4.186\times (T_{final}-95)]\\\\T_{final}=45.6^oC

Hence, the final temperature of the mixture is 45.6°C

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3 years ago
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The distance and parallax are inversely related. We can find the distance using the following equation:

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We are given the parallax of the comet relative to the moon, and we are looking for the distance to the comet relative to the moon's distance, so wee can plug in the following value:

d= \frac{1}{ \frac{1}{40} }

The distance is 40 times as far away as the moon.
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This map shows the Mid-Atlantic Ridge, which spreads approximately 2.5 cm/year. What is the rate of the spread in m/month?
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