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Zanzabum
2 years ago
6

Scanning the roadway and anticipating when you will need to stop is a great way to reduce gas usage and excessive wear on brakes

and tires
Physics
1 answer:
Serjik [45]2 years ago
8 0

It is True.

<h3>What system removes and reduces heat caused by friction?</h3>

A mechanical brake applies a friction force to convert the kinetic energy of the vehicle into thermal energy which then dissipates into the atmosphere. Braking systems which don't use friction are referred to as regenerative braking systems (RBSs).

Slowing down is the most common way of controlling the speed of an article by restraining its movement. An item moving has motor energy and to halt the article this active energy should be taken out.

Eliminating the dynamic energy can be achieved by dispersing the energy to the air through grinding or by changing over it into one more type of energy. The most well-known sort of slowing down is a mechanical brake which hinders movement through rubbing brake cushions. A mechanical brake applies a grating power to change over the motor energy of the vehicle into nuclear power which then, at that point, disperses into the atmosphere.

Braking frameworks which don't utilize grinding are alluded to as regenerative slowing mechanisms (RBSs). In RBSs, the active energy is changed over into different types of valuable energy, which can be put away for sometime in the future, expanding eco-friendliness.

To learn more about regenerative braking systems  from the given link

brainly.com/question/27799529

#SPJ4

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HELP ME <br> the bending of light when it changes media is called _________<br> u can get brainliest
olga55 [171]

Answer:

Refraction

Explanation:

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3 years ago
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Question 5 At 12:00 pm, a spaceship is at position ⎡⎣324⎤⎦ km ⎣ ⎢ ⎡ ​ 3 2 4 ​ ⎦ ⎥ ⎤ ​ km away from the origin with respect to so
Anettt [7]

Answer:

[1, 6, -2]

Explanation:

Given the following :

Initial Position of spaceship : [3 2 4] km

Velocity of spaceship : [-1 2 - 3] km/hr

Location of ship after two hours have passed :

Distance moved by spaceship :

Velocity × time

[-1 2 -3] × 2 = [-2 4 -6]

Location of ship after two hours :

Initial position + distance moved

[3 2 4] + [-2 4 -6] = [3 + (-2)], [2 + 4], [4 + (-6)]

= [3-2, 2+4, 4-6] = [1, 6, -2]

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3 years ago
A 100-kg spacecraft is in a circular orbit about Earth at a height h = 2RE .
maria [59]

To solve this problem it is necessary to apply the concepts related to the conservation of the Gravitational Force and the centripetal force by equilibrium,

F_g = F_c

\frac{GmM}{r^2} = \frac{mv^2}{r}

Where,

m = Mass of spacecraft

M = Mass of Earth

r = Radius (Orbit)

G = Gravitational Universal Music

v = Velocity

Re-arrange to find the velocity

\frac{GM}{r^2} = \frac{v^2}{r}

\frac{GM}{r} = v^2

v = \sqrt{\frac{GM}{r}}

PART A ) The radius of the spacecraft's orbit is 2 times the radius of the earth, that is, considering the center of the earth, the spacecraft is 3 times at that distance. Replacing then,

v = \sqrt{\frac{(6.67*10^{-11})(5.97*10^{24})}{3*(6.371*10^6)}}

v = 4564.42m/s

From the speed it is possible to use find the formula, so

T = \frac{2\pi r}{v}

T = \frac{2\pi (6.371*10^6)}{4564.42}

T = 8770.05s\approx 146min\approx 2.4hour

Therefore the orbital period of the spacecraft is 2 hours and 24 minutes.

PART B) To find the kinetic energy we simply apply the definition of kinetic energy on the ship, which is

KE = \frac{1}{2} mv^2

KE = \frac{1}{2} (100)(4564.42)^2

KE = 1.0416*10^9J

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What is the significance of Nucleotides in Chromosomes?​
fgiga [73]

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