No thanks. I dont buy drugs
Explanation:
this is your aur answer thank you for calcium test of tetraoxosulphate
Because the attractive forces are governed by the relationship

we know that the bond strength between the ions of opposite charge depends on the charges on the ions and the distance between the centers of the ions when they pack to form a crystal.
In the example of MgO (magnesium oxide) and NaCl, MgO has a much higher lattice energy because the ions are +2 and -2, instead of +1 and -1.
But your problem doesn't deal with the magnitude of the charge; it concerns the ionic radii.
Smaller ions are packed closer together, meaning the attractive forces are working across a smaller distance and are thus stronger. We know based on periodic trends that as you move down a group, the ion radius increases. Therefore, the lattice energy decreases.
Both Mg and Ca are alkaline earth metals (group II on the periodic table). But Mg is one row above Ca, meaning its ionic radius is smaller. Therefore, its lattice energy is larger.
<span>6.50x10^3 calories.
Now we have 4 pieces of data and want a single result. The data is:
Mass: 100.0 g
Starting temperature: 25.0°C
Ending temperature: 31.5°C
Specific heat: 1.00 cal/(g*°C)
And we want a result with the unit "cal". Now you need to figure out what set of math operations will give you the desired result. Turns out this is quite simple. First, you need to remember that you can only add or subtract things that have the same units. You may multiply or divide data items with different units and the units can combine or cancel each other. So let's solve this:
Let's start with specific heat with the unit "cal/(g*°C)". The cal is what we want, but we'ld like to get rid of the "/(g*°C)" part. So let's multiply by the mass:
1.00 cal/(g*°C) * 100.0 g = 100.0 cal/°C
We now have a simpler unit of "cal/°C", so we're getting closer. Just need to cancel out the "/°C" part, which we can do with a multiplication. But we have 2 pieces of data using "°C". We can't multiply both of them, that would give us "cal*°C" which we don't want. But we need to use both pieces. And since we're interested in the temperature change, let's subtract them. So
31.5°C - 25.0°C = 6.5°C
So we have a 6.5°C change in temperature. Now let's multiply:
6.5°C * 100.0 cal/°C = 6500.0 cal
Since we only have 3 significant digits in our least precise piece of data, we need to round the result to 3 significant figures. 6500 only has 2 significant digits, and 6500. has 4. But we can use scientific notation to express the result as 6.50x10^3 which has the desired 3 digits of significance. So the result is 6.50x10^3 calories.
Just remember to pay attention to the units in the data you have. They will pretty much tell you exactly what to add, subtract, multiply, or divide.</span>