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snow_lady [41]
3 years ago
8

How do you interpret algebraic expressions in terms of their context

Mathematics
1 answer:
SIZIF [17.4K]3 years ago
3 0
Algebraic expressions are composed of numbers and variables. To interpret them, you must have the word problem to provide you with some context. The variables signify parameters that are maybe unknown in the problem. Although unknown, they can have relationships with each other. The relationships are expressed in algebraic equations.
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pickupchik [31]
The cube root is - 9
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2 years ago
A simple die is thrown 100 times and the number five appears 14 times. Find the experimental probability of throwing a five, giv
mario62 [17]

Answer:

The experimental probability of throwing a five is 0.087.

Step-by-step explanation:

Given:

Number of trials (n) = 100

Number of times 5 appears (x) = 14

Let the event of occurrence of 5 be success and the probability represented by 'p'. So, all the other numbers occurrence is failure and its probability is represented as 'q'.

Probability of success is given as:

p=\frac{Number\ of\ favorable\ events}{Total\ number\ of\ outcomes}

Favorable event is occurrence of 5. So, its number is 1 as there is only one 5 in the die. Total outcomes are 6 as there are six numbers. So,

p=\frac{1}{6}

Now, probability of failure is given by the formula:

q=1-p=1-\frac{1}{6}=\frac{5}{6}

Now in order to find the experimental probability of 14 successes out of 100 trials, we apply Bernoulli's theorem which is given as:

P(x) = ^nC_xp^xq^{n-x}

Plug in all the given values and find the probability of 14 successes. This gives,

P(x=14)=^{100}C_{14}(\frac{1}{6})^{14}(\frac{5}{6})^{100-14}\\\\P(x=14)=0.087

Therefore, the experimental probability of throwing a five is 0.087.

8 0
3 years ago
Partial product of 563 x 410
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7 0
2 years ago
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Which shows the expression below in simplified form? (7.2 × 107) ÷ (9 × 104) A. 8 × 101 B. -1.8 × 102 C. 8 × 102 D. 8 × 104
Mariana [72]

(7.2 × 10^7) ÷ (9 × 10^4)

= (7.2 / 9) x 10^(7 - 4)

= 0.8 x 10^3

= 8 x 10^2

Answer

C. 8 × 10^2

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3 years ago
A regulation baseball field measures 90 feet between each base. What is the distance around the bases in yards?
Naddika [18.5K]
Home to 1st base = 90 ft
1st base to 2nd base = 90 ft
2nd base to 3rd base = 90 ft
3rd base to home = 90 ft
so we have a total of : (90 * 4) = 360 ft

there are 3 ft in 1 yd....
so in 360 ft, there are : 360/3 = 120 yds <==

or u could just figure it between each base....90 ft = (90/3) = 30 yds per base...and u have 4 bases....so that (4 * 30) = 120 yds
4 0
3 years ago
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