Answer:
1.) 2 over 5
2.)7.5 over 50
3.)1 1/2
5.)0.95%
6.)2.5%
7.)0.94
i cant read 9 and ten
11.)61 over 100
12.)7 over 25
13.)207 over 1000
15.)14 over 25
16.)13 over 50
17.)3 over 500
19.)5 over 8
20.)42 over 125
21.)3 over 250
I tried my best!! hope this helps you out
Answer:
The degree of fastness by which the water is rising is 210 seconds
Step-by-step explanation:
The volume of the trough when the water depth is 20 cm is first calculated
Volume of the trough (Trapezoidal Prism) = LH (A + B) × 0.5
Where L is the length of the trough, H is the height of the trough and A and B are parallel width of the top and bottom of the trough
Volume of the trough = 7 × 0.2 (0.3 + 0.7) × 0.5 = 0.7m³
The fastness at which the water is rising is = Volume ÷ water flow rate = 0.7 ÷ 0.2 = 3.5 min = 210 seconds
Answer:
5 months
Step-by-step explanation:
We assume that y represents production capacity, rather than <em>increase</em> in production capacity. Then we want to solve the 6th-degree equation ...
x^6 -25x^4 +199x^2 -4975 = 0
This can be factored in groups as ...
x^4(x^2 -25) + 199(x^2 -25) = 0
(x^4 +199)(x^2 -25) = 0
This has 4 complex solutions and 2 real solutions.
x^2 = 25
x = ±5
The duration required for capacity to reach 4975 units is 5 months.
Answer:
Step-by-step explanation:
Let as us 45 as the number we should use to get the square root in the simplest form
And then 144
The square root of a number in is simplest form means to get the number inside the radical as low as possible