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Maksim231197 [3]
3 years ago
5

Using your new formula from the previous question ,what is the side length of an equlalertal trangle that has a perimeter of 24.

6 cm?
A 73.8cm
B 12.3cm
C 8.2 cm
D 6.15 cm
and yes i know these pics have like totally noting to do with this question BUT HELP WITH THIS QUESTION PLEASEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEE!!!!!!

Mathematics
1 answer:
valina [46]3 years ago
7 0
The perimeter of an equilateral triangle is just 3s as all the sides are, well, equal :) so

P=3s and we are told that P=24.6 so

3s=24.6

s=8.2 cm
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Systems of equations with graphing
OlgaM077 [116]

Answer:

x= negative 1 and 2/5 y=1 and 3/5

Step-by-step explanation:

1. Start by putting both equations into slope-intercept form.  (y=mx+b)

-3x+3y=9

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3y=9+3x

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y=3+x

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2. Graph the equations and find where they intercept.

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2 years ago
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In January, Wally's Widget World had sales of $12,500 and expenses of $10,200. The profit for January was _____.
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Easy, $12, 500 - $10, 200 = ?
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3 years ago
A line with a slope of -2 passes thru the point (4,7)
Tpy6a [65]

Answer:

y - 7 = -2(x - 4)

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6 0
3 years ago
If <img src="https://tex.z-dn.net/?f=%5Crm%20%5C%3A%20x%20%3D%20log_%7Ba%7D%28bc%29" id="TexFormula1" title="\rm \: x = log_{a}(
timama [110]

Use the change-of-basis identity,

\log_x(y) = \dfrac{\ln(y)}{\ln(x)}

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Use the product-to-sum identity,

\log_x(yz) = \log_x(y) + \log_x(z)

to write

xyz = \dfrac{(\ln(b) + \ln(c)) (\ln(a) + \ln(c)) (\ln(a) + \ln(b))}{\ln(a) \ln(b) \ln(c)}

Redistribute the factors on the left side as

xyz = \dfrac{\ln(b) + \ln(c)}{\ln(b)} \times \dfrac{\ln(a) + \ln(c)}{\ln(c)} \times \dfrac{\ln(a) + \ln(b)}{\ln(a)}

and simplify to

xyz = \left(1 + \dfrac{\ln(c)}{\ln(b)}\right) \left(1 + \dfrac{\ln(a)}{\ln(c)}\right) \left(1 + \dfrac{\ln(b)}{\ln(a)}\right)

Now expand the right side:

xyz = 1 + \dfrac{\ln(c)}{\ln(b)} + \dfrac{\ln(a)}{\ln(c)} + \dfrac{\ln(b)}{\ln(a)} \\\\ ~~~~~~~~~~~~+ \dfrac{\ln(c)\ln(a)}{\ln(b)\ln(c)} + \dfrac{\ln(c)\ln(b)}{\ln(b)\ln(a)} + \dfrac{\ln(a)\ln(b)}{\ln(c)\ln(a)} \\\\ ~~~~~~~~~~~~ + \dfrac{\ln(c)\ln(a)\ln(b)}{\ln(b)\ln(c)\ln(a)}

Simplify and rewrite using the logarithm properties mentioned earlier.

xyz = 1 + \dfrac{\ln(c)}{\ln(b)} + \dfrac{\ln(a)}{\ln(c)} + \dfrac{\ln(b)}{\ln(a)} + \dfrac{\ln(a)}{\ln(b)} + \dfrac{\ln(c)}{\ln(a)} + \dfrac{\ln(b)}{\ln(c)} + 1

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xyz = 2 + \log_b(ac) + \log_c(ab) + \log_a(bc)

\implies \boxed{xyz = x + y + z + 2}

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2 years ago
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Viefleur [7K]

Answer:

2

Step-by-step explanation:

3 0
3 years ago
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