<h3>
Answer:</h3>
74.77 g
<h3>
Explanation:</h3>
The equation for the reaction between carbon and Oxygen is given by;
C(s) + O₂(g) → CO₂(g)
We are given;
Mass of carbon 20.4 g
Mass of Oxygen is 66.2 g
Remaining mass of Oxygen after the reaction is 11.8 g
Therefore, Carbon is the rate limiting reagent since Oxygen was in excess.
We are required to calculate the mass of carbon dioxide produced.
<h3>Step 1: Moles of Carbon produced </h3>
Moles = Mass ÷ Molar mass
Molar mass of carbon = 12.01 g/mol
Therefore;
Moles of Carbon = 20.4 g ÷ 12.01 g/mol
= 1.699 moles
<h3>Step 2: Moles of carbon dioxide produced </h3>
From the equation, 1 mole of carbon reacts to produce 1 mole of carbon dioxide.
Therefore, the mole ratio of Carbon to carbon dioxide is 1 :1
Thus, moles of carbon dioxide = Moles of carbon
= 1.699 moles
<h3>Step 3: Mass of carbon dioxide produced </h3>
Mass = Moles × Molar mass
Molar mass of carbon dioxide = 44.01 g/mol
Therefore;
Mass = 1.699 moles × 44.01 g/mol
= 74.77 g
Therefore, the mass of carbon dioxide gas produced is 74.77 g
