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vlada-n [284]
4 years ago
5

1 point

Chemistry
1 answer:
Ira Lisetskai [31]4 years ago
5 0

Answer:

<h2>Volume = 20.22 cm³</h2>

Explanation:

The density of an object can be found by using the formula

Density =  \frac{mass}{volume}

From the question

Density = 15.29 g/mL

mass = 309.109 g

To find the volume make volume the subject and solve for the volume

That's

volume =  \frac{mass}{Density}

We have

volume =  \frac{309.109}{15.29}

volume = 20.216415

We have the final answer as

Volume = 20.22 cm³ to two decimal places

Hope this helps you

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Explanation:

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An unknown compound containing only C and H was burnt, yielding 10.2 g of CO2 and 6.3 g of H2O. With a molecular weight of about
Lisa [10]

Answer:

C_2H_6

Explanation:

Hello.

In this case, we can see that the mass of carbon of the unknown compound comes from the yielded mass of carbon dioxide, thus, we compute the moles of carbon as follows:

m_C=10.2gCO_2*\frac{1molCO_2}{44gCO_2}*\frac{1mol C}{1molCO_2}=0.232 molC

Moreover, the mass of hydrogen comes from the yielded water, therefore we can also compute the moles of water:

m_H=6.3gH_2O*\frac{1molH_2O}{18gH_2O}*\frac{2molH_2}{1molH_2O}  =0.7molH

Then, to find the subscripts in the empirical formula, we divide by the moles of carbon as the smallest:

C:\frac{0.232}{0.232}=1\\ \\H:\frac{0.7}{0.232}=3

Whose molar mass is:

M_{CH_3}=12+1*3=15g/mol

Thus, the ratio of the molecular formula to the empirical formula is:

\frac{30}{15}=2

Therefore, the molecular formula is twice the empirical formula:

C_2H_6

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Class science A lunar eclipse occurs when
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Read 2 more answers
A 850.0 mL cylinder containing B2H6 at a pressure of 0.900 atm is connected by a valve to 1000 mL cylinder containing C6H6 at 60
8_murik_8 [283]

Answer:

The partial pressure of C_6H_6 when the valve is opened is 328.6 Torr.

Explanation:

Initial pressure of the C_6H_6=P_1=608.0 Torr

Initial volume of the C_6H_6=V_1=1000 mL

After opening the valve :

Final pressure or partail pressure of the C_6H_6=P_2

Final volume of the C_6H_6=V_2=1000 mL+850.0 mL=1850.0 mL

P_1V_1=P_2V_2 ( Boyle's law)

P_2=\frac{608.0 Torr \times 1000 mL}{1850.0 mL}=328.6 Torr

The partial pressure of C_6H_6 when the valve is opened is 328.6 Torr.

4 0
3 years ago
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