The buoyancy of an object is dictated by its density. So let us calculate for density, where:density = mass / volume
Calculate the volume first of a solid cube:volume = (6 cm)^3 = 216 cm^3 = 216 mL
Therefore density is:density = 270 g / 216 mLdensity = 1.25 g / mL
Therefore this object will float in the layer in which the density is more than 1.25 g / mL.
Answer:
I believe it may be-
1. Series
2. Parallel
3. Parallel
4. Series
Explanation:
In a series circuit, electricity only has one path to follow while a parallel circuit has more than one path to follow.
The question is incomplete, here is a complete question.
An arctic weather balloon is filled with 27.8 L of helium gas inside a prep shed. The temperature inside the shed is 13 ⁰C. The balloon is then taken outside, where the temperature is -9 ⁰C. Calculate the new volume of the balloon. You may assume the pressure on the balloon stays constant at exactly 1 atm. Be sure your answer has the correct number of significant digits.
Answer : The new volume of the balloon is 25.7 L
Explanation :
Charles's Law : It is defined as the volume of the gas is directly proportional to the temperature of the gas at constant pressure and number of moles.
![V\propto T](https://tex.z-dn.net/?f=V%5Cpropto%20T)
or,
![\frac{V_1}{T_1}=\frac{V_2}{T_2}](https://tex.z-dn.net/?f=%5Cfrac%7BV_1%7D%7BT_1%7D%3D%5Cfrac%7BV_2%7D%7BT_2%7D)
where,
= initial volume of gas = 27.8 L
= final volume of gas = ?
= initial temperature of gas = ![13^oC=273+13=286K](https://tex.z-dn.net/?f=13%5EoC%3D273%2B13%3D286K)
= final temperature of gas = ![-9^oC=273+(-9)=264K](https://tex.z-dn.net/?f=-9%5EoC%3D273%2B%28-9%29%3D264K)
Now put all the given values in the above equation, we get:
![\frac{27.8L}{286K}=\frac{V_2}{264K}](https://tex.z-dn.net/?f=%5Cfrac%7B27.8L%7D%7B286K%7D%3D%5Cfrac%7BV_2%7D%7B264K%7D)
![V_2=25.7L](https://tex.z-dn.net/?f=V_2%3D25.7L)
Therefore, the new volume of the balloon is 25.7 L
It is two or more objects and different things that can be removed from each other.