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hram777 [196]
3 years ago
11

Which increases the rate of a chemical reaction? A. a catalyst B. a higher volume C. a lower pressure D. a lower temperature

Chemistry
2 answers:
Tanya [424]3 years ago
6 0
A. A catalyst because it increases the time that it takes to happen
taurus [48]3 years ago
3 0
A catalyst will increase the rate of a chemical reaction by changing the reaction mechanism so that the reaction has a lower activation energy.  

a higher volume will decrease the concentrations which will intern decrease the number of collisions which will slow down the rate of the reaction since collisions between reactants are what make reactions happen.  A lower temperature causes the molecules to slow down thereby lowering the collision rate which will lower the reaction rate.  A lower pressure will lower the number of collisions which will intern result in a lower reaction rate (this can be thought of as a lower concentration since lower pressures involve less gas per unit volume)
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Answer:

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A) Devices that transfer kinetic energy have what for their source of power?
GarryVolchara [31]

Answer:

A) Devices that transfer kinetic energy have a source of power that is in motion

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¡Espero que esto ayude!

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3 years ago
Assuming that an acetic acid solution is 12% by mass and that the density of the solution is 1.00 g/mL, what volume of 1 M NaOH
Doss [256]

Explanation:

Let us assume that total mass of the solution is 100 g. And, as it is given that acetic acid solution is 12% by mass which means that mass of acetic acid is 12 g and 88 g is the water.

Now, calculate the number of moles of acetic acid as its molar mass is 60 g/mol.

    No. of moles = \frac{mass}{\text{molar mass}}

                           = \frac{12 g}{60 g/mol}

                           = 0.2 mol

Molarity of acetic acid is calculated as follows.

              Density = \frac{mass}{volume}

                 1 g/ml = \frac{100 g}{volume}

                    volume = 100 ml

Hence, molarity = \frac{\text{no. of moles}}{volume}

                           = \frac{0.2 mol}{0.1 L}

                           = 2 mol/l

As reaction equation for the given reaction is as follows.

     NaOH + CH_{3}COOH \rightarrow CH_{3}COONa + H_{2}O

So,          moles of NaOH = moles of acetic acid

Let us suppose that moles of NaOH are "x".

          x \times 1 M = 10 mL \times 2 M     (as 1 L = 1000 ml)

                        x = 20 L

Thus, we can conclude that volume of NaOH required is 20 ml.                    

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3 years ago
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