Answer:
pOH=9.9
Explanation:
pH=-log[H+]= -log[0.0000877]
=4.06
pOH+ pH=14
pOH=14-4.06= 9.91
Answer:
T₂ = 150 K
Explanation:
Given data:
Initial volume of gas = 804 mL
Initial temperature = 27°C (27+273=300 K)
Final temperature = ?
Final volume = 402 mL
Solution:
The given problem will be solve through the Charles Law.
According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.
Mathematical expression:
V₁/T₁ = V₂/T₂
V₁ = Initial volume
T₁ = Initial temperature
V₂ = Final volume
T₂ = Final temperature
Now we will put the values in formula.
V₁/T₁ = V₂/T₂
T₂ = V₂T₁/V₁
T₂ = 402 mL × 300 K / 804 mL
T₂ = 120,600 mL.K / 804 mL
T₂ = 150 K
<u>Answer:</u> The formation of given amount of oxygen gas results in the absorption of 713 kJ of heat.
<u>Explanation:</u>
To calculate the number of moles, we use the equation:

Given mass of oxygen gas = 83 g
Molar mass of oxygen gas = 32 g/mol
Putting values in above equation, we get:

For the given chemical equation:

<u>Sign convention of heat:</u>
When heat is absorbed, the sign of heat is taken to be positive and when heat is released, the sign of heat is taken to be negative.
By Stoichiometry of the reaction:
When 3 moles of oxygen gas is formed, the amount of heat absorbed is 824.2 kJ
So, when 2.594 moles of oxygen gas is formed, the amount of heat absorbed will be = 
Hence, the formation of given amount of oxygen gas results in the absorption of 713 kJ of heat.
Answer:
Yes , 5 mole of Iron Oxide has mass of 798.5 g
Explanation:
Formula of iron oxide:

Atomic mass of Fe = 55.84 amu
Atomic mass of O = 15.99 amu
Molar mass of Fe2O3 = 2(atomic mass of Fe) + 3(atomic mass of O)
= 2(55.84) + 3(15.99)
=111.68 + 47.97
= 159.69 g/mol
<u>Molar mass</u> always equal to <u>1 mole</u> of the substance.
1 mole = 159.69 g
5 mole =

= 798.45 g