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Maru [420]
2 years ago
5

Consider the combustion of methane, CH4 :

Chemistry
1 answer:
lilavasa [31]2 years ago
4 0

Answer:

CH4+3/2O2⇒CO2+2H2O

mCO2=2.8*44=123.2

Explanation:

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Uranium-235 and uranium-238 are considered isotopes of one another
viktelen [127]
Indeed they are. The uranium atoms have separate numbers of neutrons in their nuclei, but still have the same number of protons.
5 0
3 years ago
Which statement best represents a hypothesis?
mr_godi [17]

Answer:

B

Explanation: B

4 0
2 years ago
Determine the molecular formulas of these compounds:
lianna [129]

The molecular formulas of the empirical ones of P₂O₅ and CH₂O are P₄O₁₀ and C₇H₁₄O₇, respectively, knowing that their molar masses are 310 and 200.18 g/mol, respectively.  

<h3>1. Molecular formula of P₂O₅</h3>

We can calculate the molecular formula as follows:

MF = n*EF   (1)

Where:

  • MF: is the molecular formula
  • EF: is the empirical formula
  • n: is an integer  

To calculate the integer <em>n</em>, we need to use the following equation:

n = \frac{M}{M_{EF}}   (2)

Where:

  • M: is the molar mass of P₂O₅ =  310 g/mol
  • M_{EF}: is the molar mass of the empirical formula

The molar mass of the empirical formula of P₂O₅  is given by:

M_{EF} = 2A_{P} + 5A_{O}

Where:

  • A_{P}: is the atomic weight of phosphorus = 30.974 g/mol
  • A_{O}: is the <em>atomic weight</em> of oxygen = 15.999 g/mol

So, the <em>molar mass</em> of the <em>empirical formula</em> of P₂O₅  is:

M_{EF} = (2*30.974 + 5*15.999) g/mol = 141.943 g/mol  

Now, we can find the integer <em>n </em>(eq 2).

n = \frac{M}{M_{EF}} = \frac{310 \:g/mol}{141.943 \:g/mol} = 2  

Finally, after multiplying the integer <em>n</em> by the number of atoms on the empirical formula of P₂O₅, we have (eq 1):

MF = n*EF = 2 \times P_{2}O_{5} = P_{(2 \times 2)}O_{(5 \times 2)} = P_{4}O_{10}

Therefore, the molecular mass of P₂O₅ is P₄O₁₀.

<h3>2. Molecular formula of CH₂O   </h3>

We know:

  • M: molar mass of CH₂O = 200.18 g/mol

To calculate the integer <em>n</em> and so the molecular mass of the molecule, we need to calculate the<em> molar mass</em> of the <em>empirical formula</em> of CH₂O.

M_{EF} = A_{C} + 2A_{H} + A_{O} = (12.011 + 2*1.008 + 15.999) g/mol = 30.026 \:g/mol

 

Now, the integer <em>n </em>is equal to (eq 2):

n = \frac{M}{M_{EF}} = \frac{200.18 g/mol}{30.026 g/mol} \approx 7

Finally, the molecular formula of the molecule is (eq 1):

MF = n*EF = 7 \times CH_{2}O = C_{(1 \times 7)}H_{(2 \times 7)}O_{(1 \times 7)} = C_{7}H_{14}O_{7}                              

Therefore, the molecular formula of CH₂O is C₇H₁₄O₇.

Learn more about molecular formula here:

  • brainly.com/question/1247523
  • brainly.com/question/14327882

I hope it helps you!

4 0
2 years ago
Which of the following are indicators of a chemical change?
Ket [755]

Answer:

All unexpected changes: color change (two clear liquids make purple), temperature change, Odor change or formation, precipitate formation (solid forms), and the production of gas.

Explanation:

4 0
3 years ago
Meera added blue copper sulphate crystals to some water in a beaker.
professor190 [17]

Answer:

The solid crystals disappeared

Explanation:

When a soluble solid solute is added to water, the solid solute disappears after a little while. The disappearance of this solute indicates that the solute has been dissolved in water.

In this case, blue copper sulphate crystals are added to water, the blue crystals disappear leaving only a blue solution. The disappearance of these blue copper sulphate crystals indicates that the substance has dissolved in water.

7 0
3 years ago
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