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3 years ago

14

What is a wave in science terms?

1 answer:

Vlad1618 [11]3 years ago

8 0

Answer: Waves involve the transport of energy without the transport of matter. In conclusion, a wave can be described as a disturbance that travels through a medium, transporting energy from one location (its source) to another location without transporting matter.

Explanation:

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Igneous rocks with an andesitic composition ________.

slega [8]

Are found along volcanic island arcs

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3 years ago

3. Differentiate between saturated and unsaturated fats

Ket [755]

Answer:

Fats that are tightly packed with no double bonds between the fatty acids are called saturated fats.

Explanation:

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3 years ago

Convert 1.35 × 1024 atoms of carbon to moles of carbon.

Law Incorporation [45]

6.022 × 10^23 × 1.45 × 10^24 = 8.7319 × 10^47

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3 years ago

Which of the following equations can be used to determine the change in enthalpy of a system?

jonny [76]

Which of the following equations can be used to determine the change in enthalpy of a system

ΔHreaction=ΔHproducts−ΔHreactants

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4 years ago

The standard free-energy change for this reaction in the direction written is 23.8 kJ/mol. The concentrationsof the three interm

Natali [406]

Answer: The actual free-energy change for the reaction -8.64 kJ/mol.

Explanation:

The given reaction is as follows.

Fructose 1,6-bisphosphate $\rightleftharpoons$ Glyceraldehyde 3-phosphate + DHAP

For the given reaction, $\Delta G^{o}$ is 23.8 kJ/mol.

As we know that,

$\Delta G = \Delta G^{o} + RT ln Q$

Here, R = 8.314 J/mol K, T = $37^{o} C$

= (37 + 273) K

= 310.15 K

Fructose 1,6-bisphosphate = $1.4 \times 10^{-5}$ M

Glyceraldehyde 3-phosphate = $3 \times 10^{-6}$ M

DHAP = $1.6 \times 10^{-5}$ M

Expression for reaction quotient of this reaction is as follows.

Reaction quotient = $\frac{[DHAP][\text{glyceraldehyde 3-phosphate}]}{[/text{Fructose 1,6-bisphosphate}]}$

Q = $\frac{1.6 \times 10^{-5} \times 3 \times 10^{-6}}{1.4 \times 10^{-5}}$

= $3.428 \times 10^{-6}$

Now, we will calculate the value of $\Delta G$ as follows.

$\Delta G = \Delta G^{o} + RT ln Q$

= $23800 + 8.314 \times 310.15 \times ln(3.428 \times 10^{-6})$

= -8647.73 J/mol

= -8.64 kJ/mol

Thus, we can conclude that the actual free-energy change for the reaction -8.64 kJ/mol.

7 0

3 years ago