All categories

3 years ago

Is most of the bacteria on your body harmful?

Chemistry

1 answer:

TiliK225 [7]3 years ago

7 0

Answer:

No it is not, most bacteria is very helpful, it helps the body function and fight off diseases when the body is sick. Sometimes the good bacteria can't fight off the bad bacteria and will cause you to have to buy antibiotics. The antibiotics give the body a huge advantage at fighting off the disease and the body goes back to normal.

You might be interested in

If the methane contained in 2.50 L of a saturated solution at 25 ∘C was extracted and placed under STP conditions, what volume w

Sunny_sXe [5.5K]

116.6 x $10^{ -3$ } is the volume of methane contained in 2.50 L of a saturated solution at 25 ∘C that was extracted and placed under STP conditions.

<h3>What is an ideal gas equation?</h3>

The ideal gas law (PV = nRT) relates to the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

The solubility of methane in water at 25 degrees Celcius is 1.3 x $10^{ -3}$ M. It implies 1.3 x $10^{ -3}$ moles of methane are dissolved in one litre of water.

The number of moles of methane in 4 L of water can be calculated as follows:

Moles of methane = $\frac{1.3 . 10^{ -3} }{1L}$ x $\frac{4L}{1L}$

Moles of methane = 5.2 x $10^{ -3}$

STP refers to standard temperature and pressure. Under STP conditions, the temperature of the substance is 0 degrees celcius and its pressure is 1 atm.

An ideal gas is an imaginary gas comprising of a large number of randomly moving particles and the motion between such articles is considered to be perfectly elastic. The ideal gas equation describes the relationship between pressure, volume, temperature and number of moles of a gas.

The expression for ideal gas equation is as follows:

PV=nRT, where n is the moles and R is the gas constant. Then divide the given mass by the number of moles to get molar mass.

Given data:

P= 1 atm

V= ?

R= $0.082057338 \;L \;atm \;K^{-1}mol^{-1}$

T=273K

n=?

Putting value in the given equation:

$\frac{PV}{RT}=n$

5.2 x $10^{ -3} = \frac{1 \;atm\; X \;V}{0.082057338 \;L \;atm \;K^{-1}mol^{-1} X 273}$

V= 116.6 x $10^{ -3}$

Hence, 116.6 x $10^{ -3$ } is the volume of methane contained in 2.50 L of a saturated solution at 25 ∘C was extracted and placed under STP conditions.

Learn more about the ideal gas here:

brainly.com/question/27691721

#SPJ1

4 0

2 years ago

The second step is to calculate the mass of a given element ammonium nitrate (NH4NO3). We will calculate the masses of all three

crimeas [40]

Since we already have the counts of the number of moles of each element in 1 mole of ammonium nitrate (which are 2 mol N, 4 mol H, 3 mol O), we multiply each of these by the molar masses:
N has a molar mass of 14.0 g/mol, so multiplying by 2 mol N gives 28.0 g N
H has a molar mass of 1.0 g/mol, so multiplying by 4 mol H gives 4.0 g H
O has a molar mass of 16.0 g/mol, so multiplying by 3 mol O gives 48.0 g O
So there are 28.0 g N, 4.0 g H, and 48.0 g O. (The total mass would be 80.0 g ammonium nitrate.)

4 0

4 years ago

Read 2 more answers

Classify the following as either an element, compound, homogeneous mixture or

masya89 [10]

Answer:

<h2>Heterogeneous</h2>

Explanation:

<h3><em>Milk </em><em>seems</em><em> to</em><em> be</em><em> </em><em>homogeneous</em><em> mixture</em><em> </em><em>but </em><em>actually</em><em> </em><em>milk </em><em>is </em><em>a </em><em>heterogeneous</em><em> </em><em>mixture</em><em> </em><em>and </em><em>a </em><em>colloid</em><em> </em><em>solution</em><em>.</em></h3>

8 0

3 years ago

All faculty members are happy to see students help each other. Dumbledore is particularly pleased with Hermione. Though, it shou

____ [38]

Answer:

$m_{Mg}=30.8mgMg$

Explanation:

Hello,

Based on the given chemical reaction, as 31.2 mL of hydrogen are yielded, one computes its moles via the ideal gas equation under the stated conditions as shown below:

$n_{H_2}=\frac{PV}{RT}=\frac{754torr*\frac{1atm}{760torr}*0.0312L}{0.082 \frac{atm*L}{mol*K}*298.15K}=1.27x10^{-3}molH_2$

Now, since the relationship between hydrogen and magnesium is 1 to 1, one computes its milligrams by following the shown below proportional factor development:

$m_{Mg}=1.27x10^{-3}molH_2*\frac{1molMg}{1molH_2}*\frac{24.305gMg}{1molMg}*\frac{1000mgMg}{1gMg}\\m_{Mg}=30.8mgMg$

Best regards.

3 0

3 years ago

In the solution containing both 0.10 M acetic acid and 0.10 M sodium acetate, the acetic acid undergoes ionization. The chemical

Sedbober [7]

Answer:

percent ionization = 50.01%; pH = 4.75

Explanation:

To solve this question we must write the acetic acid equilibrium (Where HX will be acetic acid and X⁻ the sodium acetate):

HX(aq) ⇄ H⁺(aq) + X⁻(aq)

Where equilibrium constant, Ka, is defined as:

Ka = 1.76x10⁻⁵ = [H⁺] [X⁻] / [HX]

<em>Where the concentration of each ion is:</em>

[H⁺] = X

[X⁻] = 0.10M + X

[HX] = 0.10M - X

Replacing in Ka expression:

1.76x10⁻⁵ = [X] [0.10-X] / [0.10+X]

1.76x10⁻⁶ + 1.76x10⁻⁵X = 0.10X - X²

X² - 0.0999824 X + 1.76×10⁻⁶ = 0

X ≈ 0.1M → False solution. Decreases a lot the concentration of HX

X = 0.0000176M → Right solution.

The concentration of each ion is:

[H⁺] = 0.0000176062M

[X⁻] = 0.10M + 0.0000176M = 0.1000176M

[HX] = 0.10M - 0.0000176M = 0.0999824M

Percent ionization:

[X-] / [X-] + [HX] * 100 =

0.1000176M / 0.2M =

And pH = -log [H+]

As you can see, [H+]≈ Ka

3 0

3 years ago