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e-lub [12.9K]
3 years ago
7

Which of these best arranges the planets in the solar system in the increasing order of their period of rotation?

Chemistry
2 answers:
geniusboy [140]3 years ago
5 0
A. <span>Jupiter → Uranus → Mars → Mercury
</span>
Nastasia [14]3 years ago
4 0

Answer:

The correct answer is option A, Jupiter → Uranus → Mars → Mercury

Explanation:

Time taken by Jupiter to make one rotation = 9h 56m

Time taken by Uranus to make one rotation = 17h 14m

Time taken by Neptune to make one rotation = 16h 6m

Time taken by Mars to make one rotation = 1d 0h 37m

Time taken by Earth  to make one rotation = 23 hours, 56 minutes, and 4 seconds

Time taken by Saturn to make one rotation = 0d 10h 42m

Time taken by Venus to make one rotation = 116d 18h 0m

Time taken by Mercuryto make one rotation = 58d 15h 30m

Thus the correct order is option A,  

Jupiter (9h 56m)< Uranus(17h 14m)< Mars(1d 0h 37m) <Mercury (58d 15h 30m)

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The amount of energy available to do work after a chemical reaction has occurred is called
sveticcg [70]
Free energy is the answer i hope this helped
8 0
3 years ago
How many moles are in 100.0 g of gold?
Savatey [412]

Answer:

196.96655

Explanation:

The answer is 196.96655. I assume you are converting between grams Gold and mole. The molecular formula for Gold is Au. The SI base unit for the amount of substance is the mole.

7 0
3 years ago
Compared to the physical and chemical properties of the compound NO2, the compound N2O has
Lelu [443]

Answer:

B

Explanation:

The two compounds have different physical properties and different chemical properties despite the fact that they are formed from nitrogen and oxygen.

8 0
4 years ago
An analytical chemist is titrating of a solution of hydrazoic acid with a solution of . The of hydrazoic acid is . Calculate the
serg [7]

Answer:

pH = 12.43

Explanation:

<em>...is titrating 212.7 mL of a 0.6800 M solution of hydrazoic acid (HN3) with a 0.2900 M solution of KOH. The p Ka of hydrazoic acid is 4.72. Calculate the pH of the acid solution after the chemist has added 571.6 mL of the KOH solution to it</em>.

To solve this question we need to know that hidrazoic acid reacts with KOH as follows:

HN3 + KOH → KN3 + H2O

<em>Moles KOH:</em>

0.5716L * (0.2900mol /L) =0.1658 moles of KOH

<em>Moles HN3:</em>

0.2127L * (0.6800mol/L) = 0.1446 moles HN3

As the reaction is 1:1, the KOH is in excess. The moles in excess of KOH are:

0.1658 moles - 0.1446 moles =

0.0212 mol KOH

In 212.7mL + 571.6mL = 784.3mL = 0.7843L

The molarity of KOH = [OH-] is:

0.0212 mol KOH / 0.7843L = 0.027M = [OH-]

The pOH is defined as -log [OH-]

pOH = -log 0.027M

pOH = 1.57

pH = 14 - pOH

pH = 12.43

6 0
3 years ago
When an irregular shaped object was put in a graduated cylinder with an initial volume of 25 mL of water, the water level rose t
alexandr402 [8]

Answer:

0.24 g/mL

Explanation:

The density of an object is given by the ratio between its mass and its volume:

\rho=\frac{m}{V}

where

m is the mass of the object

V is its density

In this problem, we have:

m = 7.0 g is the mass of the object

The volume of an irregular shaped object can be measured by putting it into water, and by measuring the difference in water volume.

In this case,

V_1=25 mL is the initial volume of water

V_2=54 mL is the final volume of water

So the volume of the object is

V=V_2-V_1=54-25=29 mL

Therefore, the density of the object is:

\rho = \frac{7.0 g}{29 mL}=0.24 g/mL

7 0
3 years ago
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