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wel
3 years ago
13

Amos potted pansies and marigolds to sell in his greenhouse. During a busy weekend,he sold 48 pansies and 96 marigolds. What fra

ction of the flowers sold were marigolds
Mathematics
1 answer:
Alex777 [14]3 years ago
5 0

There are two types of flowers are given: Potted pansies and Marigolds.

Number of Potted pansies flowers sold = 48.

Number of Marigolds flowers = 96.

<em>Total number of flowers sold = Number of Potted pansies flowers sold+Number of Marigolds flowers = 48+96 = 144 flowers.</em>

Fraction of the marigolds flowers sold to the total flowers sold = \frac{96}{144}.

Reducing it into simplest fraction by dividing top and bottom by 48, we get

\frac{2}{3}.

Therefore, \frac{2}{3}rd of the flowers sold were marigolds.




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The probability that the events (a) they both picked Limca = 0.04, (b) Ademola only picked Pepsi = 0.32, (c) They both picked the same brand = 0.33 (d) They picked different brand=0.67.

<h3>What is probability?</h3>

Probability is the fraction of the required outcome event divided by the number of possible outcomes of events.

Total possible outcome of the event of picking drinks contained in the crate = 19

Hence, we can compute the following as follows;

(a) The probability they both picked Limca = (4/19)×(3/18)

Limca = 12/342

Limca = 0.04

(b) The probability Ademola only picked pepsi = 6/19

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(c) The probability they both picked the same brand = (9/19)×(8/18)+(6/19)×(5/18)+(4/19)×(3/18)

=(72+29+12)/342

= 114/342

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(d) The probability they picked different brand = (9/19)×(6/18)+(9/19)×(4/18)+(6/19)×(9/18)+(6/19)×(4/18)+(4/19)×(9/18)+(4/19)×(6/18)

The probability they picked different brand = (54+36+54+24+36+24)/342

The probability they picked different brand = 228/332

The probability they picked different brand = 0.67

Therefore, the probability for events (a) is 0.04, (b) is 0.32, (c) is 0.33 and (d) is 0.67.

Know more about probability here: brainly.com/question/24830485

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