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4 years ago

6

Simplify the radical expression below.

"TexFormula1" title="3 \sqrt{7} - \sqrt{63} " alt="3 \sqrt{7} - \sqrt{63} " align="absmiddle" class="latex-formula">

1 answer:

anzhelika [568]4 years ago

4 0

So for this, we can simplify √63 as such:

$\sqrt{63}=\sqrt{7*9}=3\sqrt{7}$

Using the simplified version of √63, we can solve it:

$3\sqrt{7} -3\sqrt{7} =0$

Zero is your final answer.

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Alexeev081 [22]

<u><em>Its 41....VERY EASY</em></u>

Let me show you:

4*4= 16 because of the exponent (2)

4 times 4 =16

Then add by 25..

Which gives u 41..

Hope this helps....

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3 years ago

Read 2 more answers

Consider the graph shown below.

Svetach [21]

Answer:

10,5

Step-by-step explanation:

After a dilation of 5, it should become 10 and 5 because it was 2,1 before.

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3 years ago

stepan [7]

Answer:

$Area = 129.5m^2$

$Perimeter = 48m$

Step-by-step explanation:

Given

See attachment

Required

Determine the area and the perimeter of the garden

Calculating Area

First, we calculate the $area\ of\ the\ rectangle$

$A_1 = L * B$

Where:

$L = 20-(3.5 +3.5)$

$B = 7$

So:

$A_1 = (20 - (3.5 + 3.5)) * 7$

$A_1 = (20 - 7) * 7$

$A_1 = 13 * 7$

$A_1 = 91$

Next, we calculate the area of the two semi-circles.

Two semi-circles = One Circle

So:

$A_2 = \pi r^2$

Where

$r = \frac{7}{2}$

$A_2 = \frac{22}{7} * (\frac{7}{2})^2$

$A_2 = \frac{22}{7} * \frac{49}{4}$

$A_2 = \frac{22}{1} * \frac{7}{4}$

$A_2 = \frac{22*7}{4}$

$A_2 = \frac{154}{4}$

$A_2 = 38.5$

Area of the garden is

$Area = A_1 + A_2$

$Area = 91 + 38.5$

$Area = 129.5m^2$

Calculating Perimeter

First, we calculate the perimeter of the rectangle

But in this case, we only consider the length because the widths have been covered by the semicircles

$P_1 = 2 * L$

Where:

$L = 20-(3.5 +3.5)$

So:

$P_1 =2 * (20-(3.5 +3.5))$

$P_1 =2 * (20-7)$

$P_1 =2 * 13$

$P_1 =26$

Next, we calculate the perimeter of the two semi-circles.

Two semi-circles = One Circle

So:

$P_2 = 2\pi r$

Where

$r = \frac{7}{2}$

$P_2 = 2 * \frac{22}{7} * \frac{7}{2}$

$P_2 = \frac{2 * 22 * 7}{7 * 2}$

$P_2 = \frac{308}{14}$

$P_2 = 22$

Perimeter of the garden is

$Perimeter = P_1 + P_2$

$Perimeter = 26 + 22$

$Perimeter = 48m$

8 0

3 years ago

Only answer for question b simple answer.

Vilka [71]

210 is the height of the new player.

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3 years ago

Geometry help please

Mariana [72]

The volume of a sphere is:

V=(4πr^3)/3, and you are told that r=5in so

V=(4π125)/3

V=500π/3 in^3

V≈523.60 in^3

4 0

3 years ago