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SVEN [57.7K]
3 years ago
8

What is the product of (3a + 2)(4a2 - 2a + 9)?

Mathematics
1 answer:
natka813 [3]3 years ago
4 0

Answer:

12a³+2a²+23a+18

Step-by-step explanation:

(3a+2)(4a²-2a+9)=

12a³-6a²+27a+8a²-4a+18=

12a³+2a²+23a+18

If you need more explanation, reply to this answer.

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Find the value of x in the triangle shown below.<br>​
Bas_tet [7]

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-2 • (-3)3 = ?<br><br> i really need help, I’m struggling so much in math.
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Answer:

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Step-by-step explanation:

6 0
2 years ago
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D<br> Evaluate<br> arcsin<br> (6)]<br> at x = 4.<br> dx
sineoko [7]

Answer:

\frac{1}{2\sqrt{5} }

Step-by-step explanation:

Let, \text{sin}^{-1}(\frac{x}{6}) = y

sin(y) = \frac{x}{6}

\frac{d}{dx}\text{sin(y)}=\frac{d}{dx}(\frac{x}{6})

\frac{d}{dx}\text{sin(y)}=\frac{1}{6}

\frac{d}{dx}\text{sin(y)}=\text{cos}(y)\frac{dy}{dx} ---------(1)

\frac{1}{6}=\text{cos}(y)\frac{dy}{dx}

\frac{dy}{dx}=\frac{1}{6\text{cos(y)}}

cos(y) = \sqrt{1-\text{sin}^{2}(y) }

          = \sqrt{1-(\frac{x}{6})^2}

          = \sqrt{1-(\frac{x^2}{36})}

Therefore, from equation (1),

\frac{dy}{dx}=\frac{1}{6\sqrt{1-\frac{x^2}{36}}}

Or \frac{d}{dx}[\text{sin}^{-1}(\frac{x}{6})]=\frac{1}{6\sqrt{1-\frac{x^2}{36}}}

At x = 4,

\frac{d}{dx}[\text{sin}^{-1}(\frac{4}{6})]=\frac{1}{6\sqrt{1-\frac{4^2}{36}}}

\frac{d}{dx}[\text{sin}^{-1}(\frac{2}{3})]=\frac{1}{6\sqrt{1-\frac{16}{36}}}

                   =\frac{1}{6\sqrt{\frac{36-16}{36}}}

                   =\frac{1}{6\sqrt{\frac{20}{36} }}

                   =\frac{1}{\sqrt{20}}

                   =\frac{1}{2\sqrt{5}}

4 0
2 years ago
Graph the line that passes through the points (6, 4)and (8, 8) and determine the equation of the line.
Lesechka [4]
Wow, what a coincidence, I just learned this at school today!
1. Slope
M= yb-ya/xb-xa
M= 8-4/8-6
M= 4/2
M= 2

2. Y-intercept
Y= mx + b
4 = (2)(6) + b
4 = 12 + b
4 = 12 + b
-12 = - 12 + b
-8 = b

Therefore, the equation is Y = 2x - 8
6 0
3 years ago
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