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Lorico [155]
3 years ago
10

Zn(s) is used to reduce other compounds in chemical reactions. If a chemist needs a substance that is more effective in its redu

cing ability, which of the following species would be the best choice?
A) Na
B) H+
C) K+
D) Cl−
Chemistry
1 answer:
givi [52]3 years ago
3 0

<u>Answer:</u> Sodium element has the highest reducing ability.

<u>Explanation:</u>

Reducing ability of an element is defined as the ability for an element to loose electrons. It helps the other element to gain electrons and thus act as reducing agent.

Reducing agent undergoes oxidation reaction.

The substance having highest positive E^o reduction potential will always get reduced and will undergo reduction reaction. Or, the substance having highest negative E^o reduction potential will always get oxidized and will undergo oxidation reaction.

For the given options:

<u>Option A:</u> Sodium

The standard reduction potential of this element will be:

Na\rightarrow Na^++e^-;E^o_{Na^+/Na}=-2.71V

<u>Option B:</u> Hydrogen ion

This element cannot loose further electrons. So, now it will gain electrons.

The standard reduction potential of this element will be:

2H^++2e^-\rightarrow H_2;E^o_{H^+/H_2}=0V

<u>Option C:</u> Potassium ion

This element cannot loose further electrons. So, now it will gain electrons.

The standard reduction potential of this element will be:

K^++e^-\rightarrow K;E^o_{K^+/K}=2.93V

<u>Option D:</u> Chlorine ion

The standard reduction potential of this element will be:

Cl_2+2e^-\rightarrow 2Cl^-;E^o_{Cl_2/Cl^-}=1.36V

As, the standard reduction potential of sodium element is more negative, it will act as reducing agent.

Hence, sodium element has the highest reducing ability.

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4 years ago
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3 years ago
What volume (mL) of the partially neutralized stomach acid was neutralized by NaOH during the titration? (portion of 25.00 mL sa
almond37 [142]

The question is incomplete, here is the complete question:

What volume (mL) of the partially neutralized stomach acid having concentration 2 M was neutralized by 0.1 M NaOH during the titration? (portion of 25.00 mL NaOH sample was used; this was the HCl remaining after the antacid tablet did it's job)

<u>Answer:</u> The volume of HCl neutralized is 1.25 mL

<u>Explanation:</u>

To calculate the volume of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of stomach acid which is HCl

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=1\\M_1=2M\\V_1=?mL\\n_2=1\\M_2=0.1M\\V_2=25mL

Putting values in above equation, we get:

1\times 2\times V_1=1\times 0.1\times 25\\\\V_1=\frac{1\times 0.1\times 25}{1\times 2}=1.25mL

Hence, the volume of HCl neutralized is 1.25 mL

3 0
3 years ago
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