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Vlada [557]
3 years ago
7

Explain chlorination of methane​

Chemistry
1 answer:
Naily [24]3 years ago
8 0

Answer:

Methane and chlorine

If a mixture of methane and chlorine is exposed to a flame, it explodes - producing carbon and hydrogen chloride. This is not a very useful reaction! The reaction we are going to explore is a more gentle one between methane and chlorine in the presence of ultraviolet light - typically sunlight. This is a good example of a photochemical reaction - a reaction brought about by light.

CH4+Cl2+energy→CH3Cl+HCl(3.4.2)

The organic product is chloromethane. One of the hydrogen atoms in the methane has been replaced by a chlorine atom, so this is a substitution reaction. However, the reaction doesn't stop there, and all the hydrogens in the methane can in turn be replaced by chlorine atoms.

Substitution reactions happen in which hydrogen atoms in the methane are replaced one at a time by chlorine atoms. You end up with a mixture of chloromethane, dichloromethane, trichloromethane and tetrachloromethane.

I hope this help you!:)

Explanation:

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Help I really need to understand this please show how you do it !!
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Answer:

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Explanation:

A limiting reactant is the lowest amount of reactant so that the reaction will stop after all that reactant used.  

To answer this question, you have to change all reactant units into moles. You have 52g HCl and its molecular mass is 36.46g/mole. The number of HCl in moles will be: 52g/ (36.46g/mole)= 1.43 moles.

In the balanced reaction formula, you can see that you need one mole of HCl and one mole of NaOH for each reaction. Both molecule's coefficient is 1.  

If we used up all NaOH, then the number of  HCl left will be:  

(moles of NaOH used * NaOH coefficient) - (moles of HCl used * HCl coefficient)  

(moles of HCl you have * HCl coefficient) - (moles of NaOH used * NaOH coefficient)    

(1.43 moles *1 ) -  (2.5 moles*1 ) = -1.07 mole

Since the result is minus, then it means we need more HCl and we can't use all NaOH.

If we used up all the HCl, then the number of NaOH left will be:  

(moles of NaOH you have* NaOH coefficient) - (moles of HCl used * HCl coefficient)  

(2.5 moles*1 )- (1.43 moles *1 )= 1.07 moles

Since the result is plus, then it means we can use all HCl.  Then HCl is the limiting reactant

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