35 Celsius minus the average 20 Celsius. going to be 15. let me know if u need anything else.
Physical changes are changes affecting the form of a chemical substance, but not its chemical composition. Physical changes are used to separate mixtures into their component compounds, but can not usually be used to separate compounds into chemical elements or simpler compounds.
Ex: cutting a paper, gaining weight, cutting hair
Isnt the basic particle that all elements are made of electrons because i know that you can get isotopes which is a whole different subject
The question is incomplete, here is the complete question:
Calculate the mole fraction of the ionic species KCl in the solution A solution was prepared by dissolving 43.0 g of KCl in 225 g of water.
<u>Answer:</u> The mole fraction of KCl in the solution is 0.044
<u>Explanation:</u>
To calculate the number of moles, we use the equation:
.....(1)
Given mass of water = 225 g
Molar mass of water = 18 g/mol
Putting values in equation 1, we get:

Given mass of KCl = 43 g
Molar mass of KCl = 74.55 g/mol
Putting values in equation 1, we get:

Mole fraction of a substance is given by:

Moles of KCl = 0.577 moles
Total moles = [0.577 + 12.5] = 13.077 moles
Putting values in above equation, we get:

Hence, the mole fraction of KCl in the solution is 0.044
The molar mass of a substance/chemical is the mass of the sample substance divided by the amount of substance in that sample.
Explanation:
- In order to calculate the atomic mass of a substance we first obtain the atomic weight of the substance from the periodic table.
- Then we count the number of atoms of the substance and multiply it with the individual atomic mass.
Molar mass of Citric Acid ( H3C6H5O7) is 192.1235 g/mol
It is calculated as :
Molar mass of C₆H₈O₇ = 6(atomic mass of C) + 8(atomic mass of H) + 7(atomic mass of O) = 6(12.0 g/mol) + 8(1.0 g/mol) + 7(16.0 g/mol) = 192.0 g/mol.
Molar mass of baking soda (NaHCO₃) is 84.0 g/mol
Molar mass of NaHCO₃ = (atomic mass of Na) + (atomic mass of H) + (atomic mass of C) + 3(atomic mass of O) = (23.0 g/mol) + (1.0 g/mol) + (12.0 g/mol) + 3(16.0 g/mol) = 84.0 g/mol.