The function represents a <em>cosine</em> graph with axis at y = - 1, period of 6, and amplitude of 2.5.
<h3>How to analyze sinusoidal functions</h3>
In this question we have a <em>sinusoidal</em> function, of which we are supposed to find the following variables based on given picture:
- Equation of the axis - Horizontal that represents the mean of the bounds of the function.
- Period - Horizontal distance needed between two maxima or two minima.
- Amplitude - Mean of the difference of the bounds of the function.
- Type of sinusoidal function - The function represents either a sine or a cosine if and only if trigonometric function is continuous and bounded between - 1 and 1.
Then, we have the following results:
- Equation of the axis: y = - 1
- Period: 6
- Amplitude: 2.5
- The graph may be represented by a cosine with no <em>angular</em> phase and a sine with <em>angular</em> phase, based on the following trigonometric expression:
cos θ = sin (θ + π/2)
To learn more on sinusoidal functions: brainly.com/question/12060967
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The answer is 96, don't ask how, just know.
Answer:
the answer is $7.78
Step-by-step explanation:
You multiply 6.5 times 1.88. Then you subtract that answer from 20.
Answer:
Step-by-step explanation:
Let us first closely examine the sequence for any mathematical correlation between the terms of sequence.
It is visualized that the series is progressing with addition of increasing even numbers starting with +6 ( +6, +8, +10, +12, +14, +16, +18 …) in the previous term to obtain next terms of the series. This logic continues for entire series.
The given series is:
1 ,7 ,15 ,25 ,37
Starting with first number of the series
1
1 + 6 = 7
7 + 8 = 15
15 + 10 = 25
25 + 12 = 37
37 + 14 = 51
51 + 16 = 67
67 + 18 = 85
The extended series is
1, 7, 15, 25, 37, 51, 67, 85
Answer:
a) P ( E | F ) = 0.54545
b) P ( E | F' ) = 0
Step-by-step explanation:
Given:
- 4 Coins are tossed
- Event E exactly 2 coins shows tail
- Event F at-least two coins show tail
Find:
- Find P ( E | F )
- Find P ( E | F prime )
Solution:
- The probability of head H and tail T = 0.5, and all events are independent
So,
P ( Exactly 2 T ) = ( TTHH ) + ( THHT ) + ( THTH ) + ( HTTH ) + ( HHTT) + ( HTHT) = 6*(1/2)^4 = 0.375
P ( At-least 2 T ) = P ( Exactly 2 T ) + P ( Exactly 3 T ) + P ( Exactly 4 T) = 0.375 + ( HTTT) + (THTT) + (TTHT) + (TTTH) + ( TTTT)
= 0.375 + 5*(1/2)^4 = 0.375 + 0.3125 = 0.6875
- The probabilities for each events are:
P ( E ) = 0.375
P ( F ) = 0.6875
- The Probability to get exactly two tails given that at-least 2 tails were achieved:
P ( E | F ) = P ( E & F ) / P ( F )
P ( E | F ) = 0.375 / 0.6875
P ( E | F ) = 0.54545
- The Probability to get exactly two tails given that less than 2 tails were achieved:
P ( E | F' ) = P ( E & F' ) / P ( F )
P ( E | F' ) = 0 / 0.6875
P ( E | F' ) = 0
