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mrs_skeptik [129]
3 years ago
9

Michael is 5 years old than rui feng and. Vishal is thrice as old as micheal if rui feng is 3 years old find Michael present age

and sum of their ages in 6 years time
Mathematics
1 answer:
lorasvet [3.4K]3 years ago
3 0

Answer:

a) Micheal's present age = 8 years old

b) The sum of their ages in 6 years time = 63 years.

Step-by-step explanation:

From the above question, we know that

Rui feng is 3 years old

We are told that

• Michael is 5 years old than Rui feng

Micheal's present age is calculated as:

= 5 + Rui feng's age

= 5 + 3 = 8 years

• Vishal is thrice as old as Micheal

Vishal's present age is calculated as

= 3(Micheal age)

= 3(8)

= 24 years.

The sum of their ages in six years time

= ( 3 + 6) +( 8 + 6) + ( 24 + 6)

= 18 + 15 + 30

= 63 years

Therefore, a) Micheal's present age = 8 years old

b) The sum of their ages in 6 years time = 63 years.

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If one three-digit number ( 0 cannot be a left digit) is chosen at random from all those that can be made from the following set
Oksana_A [137]

The probability of choosing a number that is not a multiple of 2 is P = 0.44

<h3 /><h3>How to find the probability?</h3>

We need to count the number of options for each digit.

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  • For the second digit, we have 9 options {0 ,1, 2, 3, 4, 5, 6, 7, 8}
  • For the third digit, we have 9 options {0 ,1, 2, 3, 4, 5, 6, 7, 8}.

The total number of combinations is the product between the numbers of options:

C = 8*9*9 = 648

If we want our number to not be a multiple of 2 then it must end in a odd digit, the combinations that meet that condition are:

  • For the first digit, we have 8 options {1, 2, 3, 4, 5, 6, 7, 8}
  • For the second digit, we have 9 options {0 ,1, 2, 3, 4, 5, 6, 7, 8}
  • For the third digit, we have 4 options {1, 3,  5, 7}.

C = 8*9*4 = 288

Then the probability of selecting a 3 digit number that is not a multiple of 2 is:

P = 288/648 = 0.44

If you want to learn more about probability, you can read:

brainly.com/question/251701

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