Question

A jet airliner moving initially at 858 mph

Answer 1

Answer:

1546.1 mph

Explanation:

Let's take the east direction as positive x-direction and north as positive y-direction.

The components of the initial velocity of the jet are:

$v_x = 858 mph\\v_y = 0$

while the components of the wind's velocity are

$a_x = (777)(cos 38^{\circ})=612.2 mph\\a_y = (777)(sin 38^{\circ})=478.4 mph$

So, the components of the new velocity of the jet are:

$v'_x = v_x + a_x = 858+612.2 =1470.2 mph\\v'_y = v_y+a_y = 0+478.4=478.4 mph$

And therefore, the new speed is the magnitude of the new velocity, so:

$v'=\sqrt{v'_x^2+v'_y^2 }=\sqrt{(1470.2)^2+(478.4)^2}=1546.1 mph$