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barxatty [35]
3 years ago
13

An open pipe is 1.42 m long

Physics
1 answer:
lora16 [44]3 years ago
6 0

Answer:

the fundamental frequency produced by the open pipe is 120.78 Hz

Explanation:

Given;

length of the open pipe, L = 1.42 m

speed of sound in air, v = 343 m/s

The length of the open pipe for the fundamental frequency is equivalent to half of wavelength;

L = \frac{\lambda}{2} \\\\\lambda = 2L

The fundamental frequency produced by the open pipe is calculated as;

f_o = \frac{v}{\lambda} \\\\f_o = \frac{v}{2L} \\\\f_o = \frac{343}{2 \times 1.42} \\\\f_o = 120.78 \ Hz

Therefore, the fundamental frequency produced by the open pipe is 120.78 Hz

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G of potassium reacts with 16 g of oxygen to produce 94 g of potassium oxide
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Answer:

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Explanation:

Given parameters:

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Mass of potassium oxide = 94g

Unknown:

Mass of reacting potassium = ?

Solution:

To solve this problem, we need to obtain a balanced reaction equation. Then determine the number of moles of the reactant and use it to find that of the other one.

Balanced equation:

                      4K +   O₂   →    2K₂O

  Number of moles of reacting oxygen;

       Number of moles = \frac{mass}{molar mass}

molar mass of  O₂ = 2 x 16 = 32g/mole

     Number of moles = \frac{16}{32}  = 0.5mole

From the reaction equation;

          4 mole of K reacted with 1 mole of O₂;

           x mole of K will react with 0.5 mole of O₂

Therefore, 4 x 0.5 = 2 moles of potassium.

Mass of potassium = number of moles x molar mass

              Molar mass of potassium = 39g

Mass of potassium = 2 x 39 = 78g

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