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marta [7]
4 years ago
10

Li and Raj are playing football. They take turns trying to run past each other with the football. Li weighs 125 pound and Raj we

ighs 175 pounds. Li discovers that if he changes direction quickly when running, he can always dodge out of the way before Raj can tackle him. Why is Li able to avoid Raj’s tackle? Choose the best description. Raj has more mass and therefore more inertia, so he can change his motion more easily than Li. Raj has more mass and therefore less inertia, so he can change his motion more easily than Li. Li has less mass and therefore more inertia, so he can change his motion more easily than Raj. Li has less mass and therefore less inertia, so he can change his motion more easily than Raj.
Physics
2 answers:
In-s [12.5K]4 years ago
6 0

Answer:

Li has less mass and therefore less inertia, so he can change his motion more easily than Raj.

Explanation:

correct on edge

Elenna [48]4 years ago
3 0

Answer:

Li has less mass and therefore less inertia, so he can change his motion more easily than Raj.

Explanation:

Inertia describes the resistance of an object to any change in its state of motion, and it depends on the mass of the object only. In particular:

- if an object has a large inertia (large mass), then it is more difficult to change its state of motion (i.e. to put it in motion, or to slow it down, or to change its direction of motion)

- if an object has small inertia (small mass), then it is more easy to change its state of motion

In this problem, Li has less mass than Raj, so he has less inertia, therefore he can change his motion more easily than Raj.

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Chemical equations should be balanced so that they demonstrate the law of conservation of mass. Which of the following statement
faust18 [17]

Answer:

The products must contain the same numbers and types of atoms

7 0
3 years ago
Given that the concentration of bovine carbonic anhydrase is 3.3 pmol ⋅ L − 1 and R max ( V max ) = 222 μmol ⋅ L − 1 ⋅ s − 1 , d
LuckyWell [14K]

Answer:

The turnover number of the enzyme molecule bovine carbonic anhydrase = 67,272,727.27 s^–1.

Explanation:

Given:

The concentration of bovine carbonic anhydrase = total enzyme concentration = Et = 3.3 pmol⋅L^–1 = 3.3 × 10^–12 mol.L^–1

The maximum rate of reaction = Rmax (Vmax) = 222 μmol⋅L^–1⋅s^–1 = 222 × 10^–6 mol.L^–1⋅s^–1

The formula for the turnover number of an enzyme (kcat, or catalytic rate constant) = Rmax ÷ Et = 222 × 10^–6 mol.L^–1⋅s^–1 ÷ 3.3 × 10^–12 mol.L^–1 = 67,272,727.27 s^–1

Therefore, the turnover number of the enzyme molecule bovine carbonic anhydrase = 67,272,727.27 s^–1

3 0
4 years ago
If an automobile's velocity changes from 25 m/s to 15m/s in 2s, then what is its acceleration?
tekilochka [14]
Hey!

u=25m/s
v=15m/s
t=2s
a=?

v-u=at
15-25=a×2
-10=2a
-10/2=a
a=-5m/s^2

Hope it helps...!!!
8 0
4 years ago
What is the concentration of molecular oxygen (O2) in mol/L on a June day in Toronto when atmospheric pressure is 1.0 atm and th
saveliy_v [14]

Answer:

The concentration of mole evil at oxygen on that day is 0.00858 mol/L

Explanation:

Here, we want to calculate the concentration of molecular oxygen

The pressure on that day is 1.0 atm

Since oxygen is at a concentration of 21%, the pressure of oxygen will be 21/100 * 1 = 0.21 atm

Now let’s calculate the concentration;

From Ideal gas law;

PV = nRT

This can be written as;

P/RT = n/V

The term n/V refers to concentration;

Let’s make substitutions now;

P = pressure = 0.21 atm

R = molar gas constant = 0.0821 L•atm/mol•k

T = temperature = 25 = 25 + 273.15 = 298.15 K

Substituting these values, we have;

n/V = C = 0.21/(0.0821 * 298.15) = 0.00858 mol/L

6 0
3 years ago
An Olympic diver drops from the 10 meter platform with an initial velocity of 0.0m/s. What was the vertical velocity of the dive
sammy [17]

Answer:

v=14.14 m/s

t=1.141 s    

Explanation:

Given that

h = 10 m

Initial velocity ,u = 0 m/s

We know that acceleration due to gravity g= 10 m/s²

Lets take final velocity = v

Final velocity v is given as

v² = u²+ 2 g h

v²= 0² + 2 x 10 x 10

v²= 200

v=14.14 m/s

Time taken t is given as

v= u +  a t

a=acceleration

t=time

Now by putting the values in the above equation we get

14.14= 0 + 10 x t

14.14 = 10 t

t=1.141 s

4 0
4 years ago
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