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4 years ago

10

Linda used thread to sew the booklets together she cuts 6inches of thread for each booklets how many booklets can she stitch wit

h 50inches of thread will she have any unused thread after stitching up the booklets if so how much

2 answers:

Roman55 [17]4 years ago

7 0

B*tch your so sped like wth
is wrong with u

Alex787 [66]4 years ago

5 0

$6 \times 8 = 49 - 50 = 1$

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A closed box has a square base with side length feet and height feet given that the volume of the box is 34 ft.³ express the sur

Deffense [45]

Answer:

$\dfrac{2s^3+136}{s}$

Step-by-step explanation:

Let the side length of the square base =s feet

Let the height of the box = h

Given that the volume of the box = $34$ ft^3$

Volume of the box = $s^2h$

Then:

$s^2h=34$ ft^3\\$Divide both sides by s^2\\h=\dfrac{34}{s^2}$

Surface Area of a Rectangular Prism =2(lb+bh+lh)

Since we have a square base, l=b=s feet

Therefore:

Surface Area of our closed box $= 2(s^2+sh+sh)$

$S$urface Area= 2s^2+4sh\\Recall: h=\dfrac{34}{s^2}\\$Surface Area= 2s^2+4s\left(\dfrac{34}{s^2}\right)\\=2s^2+\dfrac{136}{s}\\$Surface Area in terms of length only=\dfrac{2s^3+136}{s}$

7 0

3 years ago

Perimeter of a square painting is 216 centimeters. How long is each side?

RUDIKE [14]

Perimeter is the addition of all 4 sides and a square as all the same sides. so every side will be the same. so if you divide 216 by 4 you get 54. you can check this by adding 54+54+54+54=216 or 54x4=216

8 0

3 years ago

Don’t understand please help asap

IceJOKER [234]

First you have to solve both inequalities,

3x-1>8

3x>9

x>3

and the other one

2x≤4

x≤2

then you graph each one on the number line

the graph says or, so the solution can satisfy either equation

the solution would be all real numbers except three

the way to write it is x≠3

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4 years ago

A(r) is a function that gives the area of ta circle with the radius r. It can be written in an equation form as A(r)=3.14r^2. wh

notsponge [240]

A(r)=3.14r^2, when r=5

A(5)=3.14(5^2)

A(5)=3.14(25)

A(5)=78.5 u^2

4 0

3 years ago

What is the area of the region bounded between the curves y=x and y=sqrt(x)?

erastova [34]

Answer:

$\frac{1}{6}$

Step-by-step explanation:

y = x .....(1)

$y=\sqrt{x}$ .... (2)

By solving equation (1) and equation (2)

$x = \sqrt{x}$

$\sqrt{x}\left ( \sqrt{x}-1 \right )=0$

$\sqrt{x}=0$ or $\left ( \sqrt{x}-1 \right )=0$

x = 0, x = 1

y = 0, y = 1

A = $\int_{0}^{1}ydx(curve)-\int_{0}^{1}ydx(line)$

A = $\int_{0}^{1}\sqrt{x}dx-\int_{0}^{1}xdx$

A = $\frac{2}{3}[x^\frac{3}{2}]_{0}^{1}-\frac{1}{2}[x^2]_{0}^{1}$

A = $\frac{2}{3}-\frac{1}{2}$

A = $\frac{1}{6}$

8 0

3 years ago