Answer:
Okay I can help you to do your homework.
I'm guessing your problem is this:
y³ - 9y² + y - 9 = 0
right?
In solving this problem, I recommend doing this:
y³ - 9y² + y - 9 = 0
Factor out a y² from the first two numbers in the problem:
y²(y - 9) + (y - 9) = 0
Separate the parentheses which means y - 9 goes on one side. The y² added a one since it came from the + 1 in the middle of expression. When you're separating parentheses like this you just take the outside numbers and combine them together. Since + 1 came from the outside of the (y - 9) and y² also was sitting on the outside of (y - 9) combine them to make y² + 1. Like this:
(y² + 1)(y - 9) = 0
Now separate your two parentheses to two separate problems:
(y² + 1) = 0 and (y - 9) = 0
Now you're y² + 1 will equal:
y² = -1
y = √-1 <-- This number doesn't exist so it will be an imaginary number (i). If you guys didn't learn that in your class I recommend just leaving it as i for that part.
Now solve y - 9 = 0:
y = 9 <-- Since we added nine to both sides to get this.
So you're final answer should be y = i and 9
Answer:
10 > v (if you don't trust me, check it yourself. Subsitute v for 10 in the first equation.
Step-by-step explanation:
1) 7 > v - 3
2) add 3 to both sides
3) so 7 plus 3 equals 10
So you basically do this
7 > v - 3 (ad 3 to both sides)
You get 10 > v (which is as simplified as possible)
Hope this helps! :)
Answer:
0.234
Step-by-step explanation:
0.35x + 0.60y = 0.40(x + y) where x = vol. of 35% and y = vol. of 60%
x + y = 20
solve this system of equations
x + y = 20
-0.05x +0.20y = 0
this gives x = 16 and y = 4
so you need 16 L of 35% and 4 L of 60% solution.
