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3 years ago

14

What is the term for protection that guarantees payment to you in the event of financial loss?

1 answer:

Grace [21]3 years ago

5 0

The term for protection that guarantees payment to you in the event of financial loss is the insurance. It is <span>a practice or arrangement by which a company or government agency provides a guarantee of compensation for specified loss, damage, illness, or death in return for payment of a premium.</span>

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I have a problem can you help me on it its math its select the difference of (2x^2 -13x+7)-(1-12x)= this is were I have my probl

Finger [1]

$(2x^2 -13x+7)-(1-12x)=\\
2x^2-13x+7-1+12x=\\
2x^2-x+6$

6 0

3 years ago

Which equation represents a direct variation

Mazyrski [523]

Direct variation is is when the x and y a direct relation

without constants added or subtracted

With being times by each other

so the only one that meets the definite is the first one

y = 0.5x means y is equal to half of x. So you know that every y is directly related to half of x

7 0

3 years ago

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Laurence started with 30 pieces of candy and gave away x pieces. Beatriz started with 70 pieces of candy and gave away five time

marusya05 [52]

The answer is D she gave away x (20) pierces

4 0

3 years ago

Thomas buys tickets for his family to see a movie.

xz_007 [3.2K]

Answer:

1st option?

Step-by-step explanation:

is there more part for the question?

5 0

3 years ago

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Find (f • g) when f(x) = x^2 + 5x + 6 and g(x) = 1/x+3

Nikitich [7]

Answer:

option D

Step-by-step explanation:

$f(x) = x^2 + 5x + 6$

$g(x)= \frac{1}{x+3}$

(fog)(x) = f(g(x))

Plug in g(x) in f(x)

We plug in 1/x+3 in the place of x in f(x)

$f(g(x))= f(\frac{1}{x+3})= (\frac{1}{x+3})^2 + 5(\frac{1}{x+3}) + 6$

To simplify it we take LCD

LCD is (x+3)(x+3)

$\frac{1}{(x+3)(x+3)}+5\frac{1*(x+3)}{(x+3)(x+3)}+\frac{6(x+3)(x+3)}{(x+3)(x+3)}$

$\frac{1}{x^2+6x+9}+\frac{(5x+15)}{x^2+6x+9}+\frac{6x^2+36x+54}{x^2+6x+9}$

All the denominators are same so we combine the numerators

$\frac{1+5x+15+6x^2+36x+54}{x^2+6x+9}$

$\frac{6x^2+41x+70}{x^2+6x+9}$

Option D is correct

8 0

3 years ago

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