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Ann [662]
3 years ago
8

A ball is dropped from rest. how fast is the ball going after 3 seconds​

Physics
1 answer:
Airida [17]3 years ago
5 0

Answer:

v = 29.4m/s

Explanation:

Since the ball is dropped at rest,

u = 0m/s

a = 9.81m/s²

Using

v = u + at

After 3 seconds,

v = 0 + (9.81)(3)

v = 29.4m/s

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ryzh [129]

Answer:

C. The decrease in speed as the wave approaches shore.

Explanation:

The waves break when approaching the shore because the depth decreases. Thus, the wave travels more slowly and increases its height. There comes a time when the part of the wave on the surface travels faster than the one that travels under water, the ridge destabilizes and falls against the ground.

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3 years ago
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What is the potential energy of a 3kg ball that is on the ground?
ELEN [110]

This is where we have to admit that gravitational potential energy is
one of those things that depends on the "frame of reference", or
'relative to what?'.

         Potential energy = (mass) x (gravity) x (<em>height</em>).

So you have to specify <em><u>height above what</u></em> .

-- With respect to the ground, the ball has zero potential energy.
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-- With respect to the floor in your basement, the potential energy is

                 (3) x (9.8) x (3 meters) = 88.2 joules.

(If you let go of it, it will gain 88.2 joules of kinetic energy as it falls
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-- With respect to the top of that 10-meter hill over there, the potential
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(Its potential energy is negative. After you let go of it, you have to give it
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5 0
3 years ago
What I Know True or False. Read each statement carefully. Identify whether the statement is true or false. Write your answer on
timofeeve [1]

Answer:

1. False

2. True

3. True

4. True

5. True

6. False

7. True

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9. False

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7 0
3 years ago
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Komok [63]
I don't think so, because in order to produce an image, you need a surface behind the mirror. The light will hit the mirror, then it will bounce it back in your eyes and you see the image.
4 0
3 years ago
7 Consider two homogeneous bodies of
kupik [55]

Answer:

No, it is not necessary for them to have same mass.

Explanation:

Let both bodies have a density d1 and d2 respectively.

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we know that,

density = \frac{mass}{volume}

Hence, d1 = \frac{m1}{V1} and d2 = \frac{m2}{V2}  

Taking the ratio of densities,we get

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