Well first graph represents rectangular hyperbola
vu = c^2 ( c is constant)
AS 1/v + 1/u = 1/f
Take1/ f to be constant c
1/v = c - 1/u
it is of the form y = - x + k
Slope = -1 having intercept k as shown in fig 2
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Considering that the pulley is fixed, the force applied should be equal to the weight of the object - of 400N.

Pulleys or pulleys are mechanical tools used to assist in the movement of objects and bodies. There are two types of pulleys: fixed and movable. While the fixed pulley changes the direction of force, the moving pulley helps to decrease the force needed to move the object or body in question.
As the statement only tells us a pulley, we must consider that it is fixed, <u>because generally when it is mobile, this information is highlighted in the question</u>.
In this way, a fixed pulley only changes the direction of the applied force. Thus, the force must have the same magnitude as the weight of the object to be moved. If the bucket weighs 400N, the force applied to the pulley must be 400N.
<u>Therefore, having a fixed pulley, the force applied must be equal to the weight of the object, and will be 400N.</u>
I think is a high-pressure system because it is only in one particular area.
Any two-dimensional vector in cartesian (x,y) coordinates can be broken down into individual horizontal and vertical components using trigonometry. If a train goes up a hill with 15 degree incline at a speed of 22 m/s, the horizontal component is 22cos(15)=21.3 m/s and the vertical component is 22sin(15)=5.5 m/s.