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3 years ago

5

3y 2 +5y−10=03, y, squared, plus, 5, y, minus, 10, equals, 0 What are the solutions to the equation above? Choose 1 answer: y=-\

dfrac{5}{2}-\dfrac{\sqrt{145}}{2}

1 answer:

Ann [662]3 years ago

3 0

Answer:

$y_1=1.17\\\\y_2=-2.84$

Step-by-step explanation:

Given the following quadratic equation:

$3y^2 +5y-10=0$

You need to use the Quadratic formula to find the solutions.

The Quadratic formula is:

$y=\frac{-b\±\sqrt{b^2-4ac} }{2a}$

In this case you can identify that:

$a=3\\b=5\\c=-10$

The, substituting this values into the Quadratic formula, you get the following solutions for the given quadratic equation:

$y=\frac{-5\±\sqrt{5^2-4(3)(-10)} }{2(3)}\\\\\\y_1=1.17\\\\y_2=-2.84$

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Answer:

1) 20%

2) Choice a.

Step-by-step explanation:

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1) $P(0)$ is the population initially.

$P(1)$ is the population after a year.

$\frac{P(1)}{P(0)}$ represents the population increase factor.

So let's evaluate that fraction:

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$\frac{0.2^1}{0.2^0}=\frac{0.2}{1}=0.2$

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We want t to represent months.

A full year is 12 months, in a full year we have that $P(1)=10000(0.2)^1=10000(0.2)=2000$

So we want a new P such that $P(12)=2000$ since 12 months equals a year.

Let's look at the functions given to see which gives us this:

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Also another way to look at this:

$P(t)=10000(.2)^t$ where $t$ is in years.

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Answer:

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Answer:

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Read 2 more answers

Please help. Thank you

love history [14]

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Step-by-step explanation:

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