Question

3y 2 +5y−10=03, y, squared, plus, 5, y, minus, 10, equals, 0 What are the solutions to the equation above? Choose 1 answer: y=-\dfrac{5}{2}-\dfrac{\sqrt{145}}{2}

Answer 1

Answer:

$y_1=1.17\\\\y_2=-2.84$

Step-by-step explanation:

Given the following quadratic equation:

$3y^2 +5y-10=0$

You  need to use the Quadratic formula to find the solutions.

The Quadratic formula is:

$y=\frac{-b\±\sqrt{b^2-4ac} }{2a}$

In this case you can identify that:

$a=3\\b=5\\c=-10$

The, substituting this values into the Quadratic formula, you get the following solutions for the given quadratic equation:

$y=\frac{-5\±\sqrt{5^2-4(3)(-10)} }{2(3)}\\\\\\y_1=1.17\\\\y_2=-2.84$