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3 years ago

How many significant figures are in the quantity of 105 cm?

Mathematics

1 answer:

Sunny_sXe [5.5K]3 years ago

6 0

3 significant figures

0 is only significant if it is enclosed by significant figure.

here 0 is enclosed by significant figures 1 and 5 and is therefore significant.

105 has 3 significant figures

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Find the missing side. <br> Need help please.<br> Need to show how to get the answer.

Nutka1998 [239]

Answer:

Step-by-step explanation:

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2 years ago

Dario divides 4/6 yard of rope equally into 1/12 yard pieces for a craft project.How many pieces of rope does Dario have?Use a n

zubka84 [21]

Answer:

Eight pieces

Step-by-step explanation:

Create a number line running from 0 to 4/6.

Label the divisions as 1/6, 2/6, 3/6, and 4/6.

Divide each section in half to get small pieces of length 1/12.

Starting at zero, move to 4/6 on the number line and count the number of pieces as you go.

You count eight pieces, so Dario has eight pieces of rope.

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2 years ago

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What was the first ever Marvel comic book and when was made?

Margarita [4]

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The fantastic four in 1961

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3 years ago

Need help please and thanks

madreJ [45]

Answer:

2. n = 11

4. g = -2

6. t = 21

8. n = 4

10. y = -1

Step-by-step explanation:

2. 63 = -3(1 - 2n)

Dividing both the side by negative 3 we get

$-21=1-2n\\2n=1+21\\2n=22\\n=\frac{22}{2} \\\therefore n=11$

4. -g + 2(3 + g) = -4(g + 1)

First we will open the bracket by distributive property A( B +C) = AB + AC

$-g+2\times 3 + 2\times g = -4\times g + -4\times 1\\-g+6+ 2g=-4g-4\\\textrm{we will take all the g term the left side and the constant to the right side}\\4g-g+2g=-6-4\\5g=-10\\g=\frac{-10}{5}\\\therefore g=-2$

6.-3(t +5 ) + (4t + 2) = 8

Using distributive property A( B +C) = AB + AC we get

$-3\times t + -3\times 5 + 4t + 2=8\\-3t-15+ 4t + 2=8\\t=8+15-2\\t=21\\\therefore t=21\\$

8. -8 - n = -3(2n -4)

Using distributive property A( B +C) = AB + AC we get

$-8 - n = -3\times 2n - -3\times4\\-8-n=-6n+12\\\textrm{all the n terms to the left inside and the constant of the right-hand side}\\6n-n=8+12\\5n=20\\n=\frac{20}{5}\\ \therefore n= 4$

10. -4( 2 - y) + 3y = 3(y - 4)

Using distributive property A( B +C) = AB + AC we get

$-4\times 2 --4\times y + 3y = 3\times y -3\times 4\\-8+4y+3y =3y-12\\\textrm{all the y terms to the left side and the constant to the right side}\\4y+3y-3y=-12+8\\4y=-4\\y=\frac{-4}{4}\\ \therefore y=-1$

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3 years ago

Whats the lowest common multiple of 120 and 19600

Levart [38]

Answer:

Multiples of 120 are 120, 240, 360, 480, 600, 720, 840 etc; Multiples of 150 are 150, 300, 450, 600, 750, 900 etc; Therefore, the least common multiple of 120 and 150 is 600.

Least common multiple (LCM) of 19600 and 19619 is 384532400.

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2 years ago

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