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lorasvet [3.4K]
3 years ago
8

How many significant figures are in the quantity of 105 cm?

Mathematics
1 answer:
Sunny_sXe [5.5K]3 years ago
6 0

3 significant figures

0 is only significant if it is enclosed by significant figure.

here 0 is enclosed by significant figures 1 and 5 and is therefore significant.

105 has 3 significant figures


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Help find length of ac n explain please thanks
Debora [2.8K]

Answer:

AC = 12.5 cm

Step-by-step explanation:

use cosine law c^2 = a^2 + b^2 − 2ab cos(C)

c^2 = 6^2 + 10^2 - 2(6)(10)(cosin100)

c^2 = 156.84

c= √156.84

c= 12.5 cm

The cosine rule is used when we are given either three sides or two sides and the included angle.

6 0
2 years ago
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Finding a polynomial of a given degree with given zeros
galben [10]

Since f(x) is a polynomial with 3rd degree, then it will have 3 roots (zeroes)

One of them is real and the other two are complex conjugate roots

Since the real root is 4, then

x = 4

Since the complex root is (1 - i), then

The other root will be the conjugate of it (1 + i)

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x = (1 + i)

To find f(x) we will multiply the three factors of it

We can get the factors from the zeroes

x=4

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The first factor is (x - 4)

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The second factor is (x - 1 + i)

The third factor is (x - 1 - i)

f(x)=(x-4)(x-1+i)(x-1-i)

We will multiply them to find f(x)

\begin{gathered} (x-1+i)(x-1-i)= \\ x^2-x-ix-x+1+i+ix-i-(i^2)= \\ x^2-2x+1-(-1)= \\ x^2-2x+1+1= \\ x^2-2x+2 \end{gathered}

Multiply it by (x - 4)

\begin{gathered} f(x)=(x-4)(x^2-2x+2) \\ f(x)=x^3-2x^2+2x-4x^2+8x-8 \\ f(x)=x^3-6x^2+10x-8 \end{gathered}

The answer is

f(x)=x^3-6x^2+10x-8

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1 year ago
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Nina [5.8K]
The answer would be 34.8 I’m pretty sure
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hodyreva [135]

Answer:

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Step-by-step explanation:

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devlian [24]
7 because negitive 5 is less than 0 , but 7 is greater than both
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