Answer:
D. If the P-value for a particular test statistic is 0.33, she expects results at least as extreme as the test statistic in exactly 33 of 100 samples if the null hypothesis is true.
D. Since this event is not unusual, she will not reject the null hypothesis.
Step-by-step explanation:
Hello!
You have the following hypothesis:
H₀: ρ = 0.4
H₁: ρ < 0.4
Calculated p-value: 0.33
Remember: The p-value is defined as the probability corresponding to the calculated statistic if possible under the null hypothesis (i.e. the probability of obtaining a value as extreme as the value of the statistic under the null hypothesis).
In this case, you have a 33% chance of getting a value as extreme as the statistic value if the null hypothesis is true. In other words, you would expect results as extreme as the calculated statistic in 33 about 100 samples if the null hypothesis is true.
You didn't exactly specify a level of significance for the test, so, I'll use the most common one to make a decision: α: 0.05
Remember:
If p-value ≤ α, then you reject the null hypothesis.
If p-value > α, then you do not reject the null hypothesis.
Since 0.33 > 0.05 then I'll support the null hypothesis.
I hope it helps!
Option B. 12/ 125 is the answer.
Explanation
Total umber of sour ball candies = 50
Number of lemon candies = 12
Hence the probability to get a lemon candy is = 12/50
Number of cherry sour balls = 20
So, the probability to get a cherry sour ball = 20/50
So, to get the joint probability for a random selection to either get a lemon or cherry candy, we will multiply both the probabilities.
= 
Answer: $16.60
Step-by-step explanation:
5.80+ 3.60= 9.40+ 3.60= 13.00+ 3.60= 16.60
So after 4 weeks he earned $16.60
I believe it is the second one
