Question

How many molecules are present in 936 g of glucose (C6H12O6)?

Answer 1

The Answer would be A. 3.14*1024 molecules.

Answer 2

Answer : The correct option is, (B) $3.129\times 10^{24}$

Explanation :

First we have to calculate the moles of glucose.

$\text{Moles of glucose}=\frac{\text{Mass of glucose}}{\text{Molar mass of glucose}}=\frac{936g}{180.16g/mole}=5.195mole$

Now we have to calculate the number of molecules present in glucose.

As we know that,

1 mole of a substance contains $6.022\times 10^{23}$ number of molecules.

So, 5.195 mole of a substance contains $5.195\times (6.022\times 10^{23})=31.286\times 10^{23}=3.129\times 10^{24}$ number of molecules.

Therefore, the correct option is, (B) $3.129\times 10^{24}$