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Ede4ka [16]
3 years ago
8

How light is channelled down an optical fibre

Physics
1 answer:
coldgirl [10]3 years ago
3 0

Explanation:

Suppose you want to shine a flashlight beam down a long, straight hallway. Just point the beam straight down the hallway -- light travels in straight lines, so it is no problem. What if the hallway has a bend in it? You could place a mirror at the bend to reflect the light beam around the corner. What if the hallway is very winding with multiple bends? You might line the walls with mirrors and angle the beam so that it bounces from side-to-side all along the hallway. This is exactly what happens in an optical fiber.

The light in a fiber-optic cable travels through the core (hallway) by constantly bouncing from the cladding (mirror-lined walls), a principle called total internal reflection. Because the cladding does not absorb any light from the core, the light wave can travel great distances.

However, some of the light signal degrades within the fiber, mostly due to impurities in the glass. The extent that the signal degrades depends on the purity of the glass and the wavelength of the transmitted light (for example, 850 nm = 60 to 75 percent/km; 1,300 nm = 50 to 60 percent/km; 1,550 nm is greater than 50 percent/km). Some premium optical fibers show much less signal degradation -- less than 10 percent/km at 1,550 nm.

1

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If ∆H = + VE , THEN WHAT REACTION IT IS<br>1) exothermic<br>2) endothermic​
podryga [215]

Answer:

endothermic

Explanation:

An endothermic is any process with an increase in the enthalpy H (or internal energy U) of the system. In such a process, a closed system usually absorbs thermal energy from its surroundings, which is heat transfer into the system.

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3 years ago
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Zanzabum

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A fire hose is turned on the door of a burning building in order to knock the door down. This requires a force of 1000 N. If the
Sedaia [141]

Answer:

Minimum velocity is 25m/s

Explanation:

Given force F =1000N

Mass flow rate m/t= 40kg/s

Velocity=v

Recall Newton second law of motion F =MV/t

1000=40v

V=1000/40

25m/s

8 0
3 years ago
An electron is accelerated from rest through a potential difference. After acceleration the electron has a de Broglie wavelength
Vladimir [108]

Answer:

3x10⁴v

Explanation:

Using

Wavelength= h/ √(2m.Ke)

880nm = 6.6E-34/√ 2.9.1E-31 x me

Ke= 6.6E-34/880nm x 18.2E -31.

5.6E-27/18.2E-31

= 3 x 10⁴ Volts

4 0
4 years ago
Early skeptics of the idea of a rotating Earth said that the fast spin of Earth would throw people at the equator into space. Th
dedylja [7]

Answer:

a) v = R w = 6400000 m *7.27 x10^{-5} \frac{rad}{s}= 465.421 m/s

b) F_c = 98 kg* (6400000 m) (7.27 x10^{-5} \frac{rad}{s})^2 = 3.316N

c) W = 98kg * 9.8 m/s^2 = 960.4 N

d) W_a = 960.4 N -3.316 N = 957.04 N

Explanation:

For this case we have the following data:

R= 6.4x10^6 m = 6400000 m represent the radius of the Earth

The gravity for this case is assumed g = 9.8 m/s^2

m =98 kg represent the mass of the person

w=\frac{2\pi}{T} =\frac{2\pi}{24 hr *\frac{3600 s}{1hr}}= 7.27 x10^{-5} \frac{rad}{s} represent the angular velocity for the Earth

Part a

Since we need to find the speed of the person at the equator we can use the following formula:

v = R w = 6400000 m *7.27 x10^{-5} \frac{rad}{s}= 465.421 m/s

Part b

We can use the formula for the centripetal force for the person at the equator to allow the rotation like this:

F_c = m R w^2

And if we replace we got:

F_c = 98 kg* (6400000 m) (7.27 x10^{-5} \frac{rad}{s})^2 = 3.316N

Part c

The weight of the person is just defined as:

W = mg

And if we replace we got:

W = 98kg * 9.8 m/s^2 = 960.4 N

Part d

The normal force of Earth on the person represent the apparent weight and is given by:

W_a = W - F_c

And since we have the weight and the centripetal forc we can replace like this:

W_a = 960.4 N -3.316 N = 957.04 N

5 0
4 years ago
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