3 years ago

A clothes dryer uses about 29 amps of current from a 240 volt line. How much power does it use?

Physics

1 answer:

erica [24]3 years ago

4 0

Power = Voltage × Current. 29A×240v = 6,960 watts

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The distance from the earth to a star that has identical apparent and absolute magnitudes is ____ .

PSYCHO15rus [73]

I think it's distance.

5 0

3 years ago

A railroad track and a road cross at right angles. An observer stands on the road and watches an eastbound train traveling at 60

mamaluj [8]

Answer:

After 4 s of passing through the intersection, the train travels with 57.6 m/s

Solution:

As per the question:

Suppose the distance to the south of the crossing watching the east bound train be x = 70 m

Also, the east bound travels as a function of time and can be given as:

y(t) = 60t

Now,

To calculate the speed, z(t) of the train as it passes through the intersection:

Since, the road cross at right angles, thus by Pythagoras theorem:

$z(t) = \sqrt{x^{2} + y(t)^{2}}$

$z(t) = \sqrt{70^{2} + 60t^{2}}$

Now, differentiate the above eqn w.r.t 't':

$\frac{dz(t)}{dt} = \frac{1}{2}.\frac{1}{sqrt{3600t^{2} + 4900}}\times 2t\times 3600$

$\frac{dz(t)}{dt} = \frac{1}{sqrt{3600t^{2} + 4900}}\times 3600t$

For t = 4 s:

$\frac{dz(4)}{dt} = \frac{1}{sqrt{3600\times 4^{2} + 4900}}\times 3600\times 4 = 57.6\ m/s$

4 0

3 years ago

An automobile is sitting on a hill which is 20 m higher than ground level. Find the mass of the automobile if it contains 362,60

mr Goodwill [35]

M= ?
g=9.8 m/s (2)
h=20 m

Eg=362,600 J
Eg/mg

362,600 J/9.8 m/s (2) x 20 m
=1,850 m

6 0

3 years ago

. You are in an airplane flying over the ocean. How could you most accurately determine your distance from the water?

pshichka [43]

Answer:

i dont nobhhjkkkkkkuii

Explanation:

hjko0fraer

8 0

1 year ago

2.5 gram sample of a radioactive element was formed in a 1960 explosion of an atomic bomb at Johnson Island in the Pacific Test

kow [346]

Answer:

0.15625 grams

Explanation:

Half life: It is related to the decay of radioactive material. The duration in which half of the material will be degraded/decayed. That means after half life 50% of the radioactive material will be left. Here the half life is 28 years.

Initial quantity of the sample: 2.5 grams.

After 28 years, the leftover quantity = 1.25 grams

After 56 years, the leftover quantity = 0.625 grams

After 84 Years, the leftover quantity = 0.3125 grams

After 112 years, the leftover quantity = 0.15625 grams

5 0

3 years ago