We will calculate the magnetic field for each of the supplied currents. Recall that the magnetic field is equivalent to the product between the permeability of free space, the current, and the distance. Both have their respective vector direction, so their final magnitude will be the scalar form of the values found,
For the current of 30 A
Here,
= Permeability at free space
I = Current
r = Distance between them
For the second current of 40A,
The wire goes through z-direction, then the Magnetic field is in x-direction positive.
Finally the magnitude will be
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Answer:
(3) The period of the satellite is independent of its mass, an increase in the mass of the satellite will not affect its period around the Earth.
(4) he gravitational force between the Sun and Neptune is 6.75 x 10²⁰ N
Explanation:
(3) The period of a satellite is given as;
where;
T is the period of the satellite
M is mass of Earth
r is the radius of the orbit
Thus, the period of the satellite is independent of its mass, an increase in the mass of the satellite will not affect its period around the Earth.
(4)
Given;
mass of the ball, m₁ = 1.99 x 10⁴⁰ kg
mass of Neptune, m₂ = 1.03 x 10²⁶ kg
mass of Sun, m₃ = 1.99 x 10³⁰ kg
distance between the Sun and Neptune, r = 4.5 x 10¹² m
The gravitational force between the Sun and Neptune is calculated as;
Answer:
Fluorine is the most reactive element
A.) attract to each other
