Answer:
The value is ![f = 0.05 \ Hz](https://tex.z-dn.net/?f=f%20%20%3D%20%200.05%20%5C%20Hz)
Explanation:
From the question we are told that
The mass of the car is
The period of the circular motion is ![T = 20 \ s](https://tex.z-dn.net/?f=T%20%20%3D%20%2020%20%5C%20%20s)
The radius is ![r = 80 \ m/s](https://tex.z-dn.net/?f=r%20%3D%20%2080%20%5C%20%20m%2Fs)
Generally the frequency of the circular motion is
![f = \frac{1}{T }](https://tex.z-dn.net/?f=f%20%20%3D%20%20%20%5Cfrac%7B1%7D%7BT%20%7D)
=> ![f = \frac{1}{ 20 }](https://tex.z-dn.net/?f=f%20%20%3D%20%20%20%5Cfrac%7B1%7D%7B%2020%20%20%7D)
=> ![f = 0.05 \ Hz](https://tex.z-dn.net/?f=f%20%20%3D%20%200.05%20%5C%20Hz)
<span>a+b= ?
3i +3j + (3i -3j) = ?
3i + 3j + 3i -3j =?
= 6i + 0j</span>
There's not enough information to find an answer.
I think the idea here is that in descending (416 - 278) = 138 meters,
the glider gives up some gravitational potential energy, which
becomes kinetic energy at the lower altitude. This is all well and
good, but we can't calculate the difference in potential energy
without knowing the mass of the glider.
Answer:
4.7 m³
Explanation:
We'll use the gas law P1 • V1 / T1 = P2 • V2 / T2
* Givens :
P1 = 101 kPa , V1 = 2 m³ , T1 = 300.15 K , P2 = 40 kPa , T2 = 283.15 K
( We must always convert the temperature unit to Kelvin "K")
* What we want to find :
V2 = ?
* Solution :
101 × 2 / 300.15 = 40 × V2 / 283.15
V2 × 40 / 283.15 ≈ 0.67
V2 = 0.67 × 283.15 / 40
V2 ≈ 4.7 m³
Answer:
no it can not effect the speed of sound not shure tho