I think they are called Faults.
Answer:
Ammonia in the gaseous form or in aqueous solution neutralises acids forming the respective ammonium salts because it is basic in nature.
In order to find out the number of electrons present in s orbital of Phosphorous we have to write the electronic configuration of phosphorous.
As the Atomic number of Phosphorous is 15 so it will have 15 electrons in neutral state. So,
P = 15 = 1s², 2s², 2p⁶, 3s², 3p³
Now analyzing electronic configuration, we found that it contains 3 s orbitals, i.e. 1s, 2s and 3s, and each s orbital is completely filled with two electrons each.
Result:
Therefore, a total of six electrons are present in all s orbitals of neutral Phosphorous Atom.
I believe the answer is mass :)
Answer:
Use a spoon, scoop up a small amount of the syrup. When you do, you won't be able to see any sugar crystals in the liquid which is water.