Answer:
130ml of HCl(36%) in 4.90L solution => pH = 1.50
Explanation:
Need 4.90L of HCl(aq) solution with pH = 1.5.
Given pH = 1.5 => [H⁺] = 10⁻¹·⁵M = 0.032M in H⁺
[HCl(36%)] ≅ 12M in HCl
(M·V)concentrate = (M·V)diluted
12M·V(conc) = 0.032M·4.91L
=> V(conc) needed = [(0.032)(4.91)/12]Liters = 0.0130Liters or 130 ml.
Mixing Caution => Add 131 ml of HCl(36%) into a small quantity of water (~500ml) then dilute to the mark.
Answer:
Here's what I get
Explanation:
A substance with ρ < 1.36 g/cm⁻³ will float on corn syrup.
A substance with ρ > 1.36 g/cm⁻³ will sink in corn syrup
The picture isn’t included
It's B
because ionic molecules are not soluble in oil
polar molecules are soluble in water
nonpolar molecules are not soluble in water
and metals are not soluble neither in water nor in oil
Answer:
C) 107 g
Explanation:
Step 1: Calculate the molar mass of Ca(NO₃)₂
We can calculate the molar mass of Ca(NO₃)₂ by adding the masses of its elements.
M = 1 × Ca + 2 × N + 2 × 3 × O
M = 1 × 40.08 g/mol + 2 × 14.01 g/mol + 6 × 16.00 g/mol
M = 164.10 g/mol
Step 2: Calculate the mass corresponding to 0.650 moles of Ca(NO₃)₂
We multiply the number of moles by the molar mass.
0.650 mol × 164.10 g/mol = 107 g
