Calculate the percentage of limestone that dissolved from each solution. Start by subtracting the final mass from the initial ma
ss. Divide that number by the initial mass. Then multiply the result by 100 to make it a percent. Use this formula:
% dissolved= initial mass- final mass/ initial mass x 100
ORIGINAL: 0% Acid 33% Acid 66% Acid 100% Acid
Initial Mass (g) 10.0 10.1 10.0 9.9
Final Mass (g) 10.0 10.0 9.8 9.5
Record the percentage of limestone dissolved in each acid concentration.
Look at attched...
% dissolved= initial mass- final mass/ initial mass x 100
ORIGINAL: 0% Acid 33% Acid 66% Acid 100% Acid
Initial Mass (g) 10.0 10.1 10.0 9.9
Final Mass (g) 10.0 10.0 9.8 9.5
Record the percentage of limestone dissolved in each acid concentration.
Look at attched...
1 answer:
9514 1404 393
Answer:
see attached
Explanation:
It works nicely to let a spreadsheet do the calculations described in your problem statement.
You don't actually have to multiply by 100 to make the number a percent. Spreadsheets have the capability to show a value as a percentage just by changing the format.
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Answer:
The mass of Na₂O that can be produced by the chemical reaction of 4.0 grams of sodium with excess oxygen in the reaction is 5.39 grams.
Explanation:
You know the balanced reaction:
4 NA + O₂ ⟶ 2 Na₂O
By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction) react and are produced:
- Na: 4 moles
- O₂: 1 mole
- Na₂O: 2 moles
Being:
- Na: 23 g/ole
- O: 16 g/mole
the molar mass of the compounds participating in the reaction is:
- Na: 23 g/mole
- O₂: 2*16 g/mole= 32 g/mole
- Na₂O: 2*23 g/mole +16 g/mole= 62 g/mole
Then by stoichiometry of the reaction they react and are produced:
- Na: 4 moles* 23 g/mole= 92 g
- O₂: 1 mole*32 g/mole= 32 g
- Na₂O: 2 moles* 62 g/mole= 124 g
Then you can apply the following rule of three: if 92 grams of Na produce 124 grams of Na₂O, 4 grams of Na, how much mass of Na₂O does it produce?
mass of Na₂O=5.39 g
<em><u>The mass of Na₂O that can be produced by the chemical reaction of 4.0 grams of sodium with excess oxygen in the reaction is 5.39 grams.</u></em>