Calculate the percentage of limestone that dissolved from each solution. Start by subtracting the final mass from the initial ma
ss. Divide that number by the initial mass. Then multiply the result by 100 to make it a percent. Use this formula:
% dissolved= initial mass- final mass/ initial mass x 100
ORIGINAL: 0% Acid 33% Acid 66% Acid 100% Acid
Initial Mass (g) 10.0 10.1 10.0 9.9
Final Mass (g) 10.0 10.0 9.8 9.5
Record the percentage of limestone dissolved in each acid concentration.
Look at attched...
% dissolved= initial mass- final mass/ initial mass x 100
ORIGINAL: 0% Acid 33% Acid 66% Acid 100% Acid
Initial Mass (g) 10.0 10.1 10.0 9.9
Final Mass (g) 10.0 10.0 9.8 9.5
Record the percentage of limestone dissolved in each acid concentration.
Look at attched...
1 answer:
9514 1404 393
Answer:
see attached
Explanation:
It works nicely to let a spreadsheet do the calculations described in your problem statement.
You don't actually have to multiply by 100 to make the number a percent. Spreadsheets have the capability to show a value as a percentage just by changing the format.
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Answer:
23.0733 L
Explanation:
The mass of hydrogen peroxide present in 125 g of 50% of hydrogen peroxide solution:
Mass = 62.5 g
Molar mass of = 34 g/mol
The formula for the calculation of moles is shown below:
Thus, moles are:
Consider the given reaction as:
2 moles of hydrogen peroxide decomposes to give 1 mole of oxygen gas.
Also,
1 mole of hydrogen peroxide decomposes to give 1/2 mole of oxygen gas.
So,
1.8382 moles of hydrogen peroxide decomposes to give
So,
Pressure = 746 / 760 atm = 0.9816 atm
Temperature = 27 °C
The conversion of T( °C) to T(K) is shown below:
T(K) = T( °C) + 273.15
So,
T₁ = (27 + 273.15) K = 300.15 K
Using ideal gas equation as:
PV=nRT
where,
P is the pressure
V is the volume
n is the number of moles
T is the temperature
R is Gas constant having value = 0.0821 L.atm/K.mol
Applying the equation as:
0.9816 atm × V = 0.9191 mol × 0.0821 L.atm/K.mol × 300.15 K
<u>⇒V = 23.0733 L</u>