All categories

2 years ago

Please help. I only need parts a and b.

Mathematics

1 answer:

Alex2 years ago

7 0

Answer:

oI know that for a they are pretty much the same shape im not sure how else to desribe it sorry

Step-by-step explanation:

You might be interested in

What is the value of h in the diagram below? If necessary, round your answer

Nookie1986 [14]

Answer:

I believe the answer would be B. 9.1

Step-by-step explanation:

I am not 100% sure this is correct since I haven't done a problem like this in years but i'm like 90% sure.

4 0

2 years ago

{ y = x + 5 ,4x + y =20 }

Tju [1.3M]

4x+(x+5)=20
5x+5=20
5x=15
X=3

4 0

3 years ago

Cuanto es 50 gramos en kilos por fa

tatuchka [14]

0.05 kilogramos.................

8 0

2 years ago

Read 2 more answers

Sketch the graph of y (x +3)2-4 and identify the axis of symmetry.

masya89 [10]

The axis of symmetry is at x = -3.

This can be found by looking at the basic form of vertex form:

y = (x - h)^2 + k

In this basic form the vertex is (h, k). By looking at what is plugged into the equation, it is clear that h = -3 and k = -4. This means the vertex is at (-3, -4).

It is a fact that the axis of symmetry is a vertical line of x = (vertex value of x). So we can determine that the axis of symmetry is at x = -3

6 0

3 years ago

Consider the following. f(x) = x5 − x3 + 6, −1 ≤ x ≤ 1 (a) Use a graph to find the absolute maximum and minimum values of the fu

kykrilka [37]

ANSWER

See below

EXPLANATION

Part a)

The given function is

$f(x) = {x}^{5} - {x}^{3} + 6$

From the graph, we can observe that, the absolute maximum occurs at (-0.7746,6.1859) and the absolute minimum occurs at (0.7746,5.8141).

b) Using calculus, we find the first derivative of the given function.

$f'(x) = 5 {x}^{4} - 3 {x}^{2}$

At turning point f'(x)=0.

$5 {x}^{4} - 3 {x}^{2} = 0$

This implies that,

${x}^{2} (5 {x}^{2} - 3) = 0$

${x}^{2} = 0 \: or \: 5 {x}^{2} - 3 = 0$

$x = - \frac{ \sqrt{15} }{5} \: or \: x = 0 \: \: or \: x =\frac{ \sqrt{15} }{5}$

We plug this values into the original function to obtain the y-values of the turning points

$( - \frac{ \sqrt{15} }{5} , \frac{1}{125} ( 6 \sqrt{15} +750)) \:and \: (0, - 6) \: and\: ( \frac{ \sqrt{15} }{5} , \frac{1}{125} ( - 6 \sqrt{15} +750))$