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deff fn [24]
3 years ago
15

HELP ASAP!!! PLEASE!!!! A driver traveling on the highway at 100km/hr notices the speed limit changes to 50km/hr as a speed came

ra is coming up. The driver takes 0.9s to slow down to 50km/hr with constant acceleration. How many meters does the driver travel while slowing down?
Physics
1 answer:
Talja [164]3 years ago
8 0

Answer:

90m

Explanation:

Speed * time

100*0.9=90m

hope this helped xx

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raketka [301]
<span>It can form four covalent bonds. </span>
8 0
3 years ago
Two positively charged particles are separated on an axis by 0.1 meters, and q1 has a 6 µC charge and q2 has a 2 µC charge. Reca
Vlada [557]

Answer:

Force between two charges is 10.8 N

both charges are positive nature charge so they both repel each other and hence q2 will move away from charge q1

Explanation:

As we know that the force between two charge particles is given by Coulomb's law of electrostatics

So we will say it as

F = \frac{kq_1q_2}{r^2}

here we know that

q_1 = 6\mu C

q_2 = 2\mu C

d = 0.1 m

F = \frac{8.99 \times 10^9(6 \mu C)(2\mu C)}{0.1^2}

F = 10.8 N

Since both charges are positive nature charge so they both repel each other and hence q2 will move away from charge q1

5 0
3 years ago
Read 2 more answers
Planets A and B have the same size, mass, and direction of travel, but planet A is traveling through space at half the speed of
Ganezh [65]

Answer:

B. You would weigh the same on both planets because their masses and the distance to their centers of gravity are the same.

Explanation:

Given that Planets A and B have the same size, mass.

Let the masses of the planets A and B are m_A and m_B respectively.

As masses are equal, so m_A=m_B\cdots(i).

Similarly, let the radii of the planets A and B are r_A and r_B respectively.

As radii are equal, so r_A=r_B\cdots(ii).

Let my mass is m.

As the weight of any object on the planet is equal to the gravitational force exerted by the planet on the object.

So, my weight on planet A, w_A= \frac {Gm_Am}{r_A^2}

my weight of planet B, w_B=\frac {Gm_Bm}{r_B^2}

By using equations (i) and (ii),

w_B=\frac {Gm_Am}{r_A^2}=w_A.

So, the weight on both planets is the same because their masses and the distance to their centers of gravity are the same.

Hence, option (B) is correct.

4 0
3 years ago
calculate the energy spent on spraying a drop of mercury of 1 cm radius into 10^6 droplets all of same radius. surface tension o
WARRIOR [948]

Answer:

ANS : .Energy spent on spraying =4.3542*10^{-4}J

Explanation:

<em>Given:</em>

  • <em>Radius of mercury = 1cm initially ;</em>
  • <em>split into 10^{6} drops ;</em>

Thus, volume is conserved.

i.e ,

\frac{4}{3} \pi R_{o}^{3} = 10^{6}*\frac{4}{3} \pi R_{n}^{3}\\R_{n}=\frac{R_{o}}{10^{2}} = \frac{1cm}{100} = 0.01 cm

  • Energy of a droplet = TΔA

Where ,

  • <em>T is the surface tension </em>
  • <em>ΔA is the change in area</em>

Initial energy E_{i} = T*A_{i}\\= 0.0035 * 4 *\pi *0.01^{2}\\=4.398*10^{-6}J

Final energy E_{f}=10^{6}*T*A_{f}\\=10^{6}*0.0035*4*\pi *(0.0001)^2\\=4.39823*10^{-4}

∴  .Energy spent on spraying = =E_{f}-E{i}\\=(439.823-4.39823)*10^{-6}\\=4.3542*10^{-4}J

ANS : .Energy spent on spraying =4.3542*10^{-4}J

6 0
3 years ago
What is a rumor wave ?
Radda [10]

Answer:

Following are the answer to this question:

Explanation:

The wave is propagating at the incident wave which focuses on the stretchy and rotational inertia features of the whole medium via a material system.  For both the mechanical waves there are many two basic types of incident waves: quality management program and transverse waves.

The rumor is also known as the "Norman Rockwell", in which the environment of some of the greatest physics attempts of our time, it pays to remain suspicious when remarkable reports of historical findings are made on social media.

3 0
3 years ago
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