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Rufina [12.5K]
3 years ago
7

Plzz answer this question correctly

Physics
1 answer:
Leno4ka [110]3 years ago
6 0

Answer:

by reducing friction.....

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A pitcher hurls a 0.25kg ball around a vertical circular path of radius 0.6 m, applying a tangential force of 30N, before releas
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Thank you for posting your question here at brainly. Below is the solution:

Ke up top = 1/2*.25 *225 
<span>gain of Pot energy = .25*9.81*1.2 </span>
<span>work input = (1/4)(2 pi *.6)*30 </span>

<span>so </span>
<span>sum of those 3 energies = </span>
<span>(1/2)(.25)v^2</span>
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A motorist travels 130 km in 2 hours.
ohaa [14]
The motorist is traveling at 65 miles per hour
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3 years ago
A 50.0-kg block is being pulled up a 13.0° slope by a force of 250 N which is parallel to the slope, but the block does not slid
Elan Coil [88]

<span>Weight of block, Wb = mass*gravity = 50*9.8 = 490 N</span>

Since block is being pulled up by a 13-degree slope

Therefore, Force which is acting parallel to the slop:

<span> F p =490 Sin </span>13^{0}= 110.2N

Force which is acting perpendicular to the slope:

<span> Fv =490 Cos</span>13^{0} = 477.4 N

Net force can be given as follows:

<span>F n = (250 - 110.2 - 0.2*</span>477.4) N

<span>Fn=44.3N</span>

Now acceleration is given by the ratio of force to mass

<span>a = Fn/m</span>

<span>=44.3/50 = 0.89 ms^<span>-2</span></span>

8 0
3 years ago
A square wave has amplitude 0 V for the low voltage and 4 V for the high voltage. Calculate the average voltage by integrating o
Margarita [4]

Answer:

V_{average} = \frac{1}{2}  V_o  ,     V_{average} = 2 V

Explanation:

he average or effective voltage of a wave is the value of the wave in a period

            V_average = ∫ V dt

in this case the given volage is a square wave that can be described by the function

           V (t) = \left \{ {{V=V_o \ \ \  t<  \tau /2} \atop {V=0 \ \  \ \  t> \tau /2 }   } \right.

to substitute in the equation let us separate the into two pairs

             V_average = \int\limits^{1/2}_0 {V_o} \, dt + \int\limits^1_{1/2} {0} \, dt

             V_average = V_o \ \int\limits^{1/2}_0 {} \, dt

             V_{average} = \frac{1}{2}  V_o

we evaluate  V₀ = 4 V

             V_{average} = 4 / 2)

             V_{average} = 2 V

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A motor has a rating power of 20 W and motor is used for 10 s. Calculate the
zepelin [54]

Explanation:

oii ay school ens?

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