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Rufina [12.5K]
3 years ago
7

Plzz answer this question correctly

Physics
1 answer:
Leno4ka [110]3 years ago
6 0

Answer:

by reducing friction.....

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What is the purpose of a rearview mirror in a car?
Shalnov [3]
The third choice.

The driver wants to see the object that is behind him. The light reflects off the mirror into the eyes of the driver portraying the object behind him
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3 years ago
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Which system of government has a leader that takes power by force
kvv77 [185]

Answer:

The Autocratic system of governance

Explanation:

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5 0
3 years ago
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A guitar string with a linear density of 2.0 g/m is stretched between supports that are 60 cm apart. The string is observed to f
Butoxors [25]

<h2>The frequency of driver is 700 Hz</h2>

Explanation:

The frequency of wave in a string is given by the relation

n = \frac{p}{2l} \sqrt{\frac{T}{m} }

here n is the frequency

p is the number of antinodes and l is the length of string .

T is the tension in string and m is the mass per unit length

Thus 420 =\frac{3}{120} \sqrt{\frac{T}{2} }            I

Now if there is 5 antinodes , the value of p = 5

Thus n = \frac{5}{120} \sqrt{\frac{T}{2} }          II

Dividing II by I , we have

n/420 = 5/3

or n = 5/3 x 420 = 700 Hz

3 0
3 years ago
Question 2
yarga [219]

Answer:

24.4 m

Explanation:

first we have to calculate how long the cat will be in the air, in vertical direction this is free fall from 4m (poor cat, hope he survived) with acceleration of g=9.81 m/s^2

time = sqrt ( 2 * height / g)

time = sqrt (2 * 4 / 9.81)

time = 0,903 s

then we know his horizontal flight was 22 m long, so ve can calculate verical speed

speed = length / time

speed = 22 m / 0,903 s

speed = 24.363 m

as you are asked to give 3 significant numbers answer is 24,4 m

8 0
3 years ago
6. A 0.09 kg arrow hits a target at 22 m/s and penetrates 4 cm before stopping.
tatyana61 [14]
A ) v = v o - a t
0 = 22 - a · t
a · t = 22
d = v o · t - a t²/2
0.04 = 22 t - 22 t / 2
0.04 = 11 t
t = 0.04 : 11 = 0.003636 s
a = 22 / t
a = 6050 m/s²
F = m · a = 0.09 kg · 6050 m/s²
F ( target→arrow) = - 544.5 N
b ) F ( arrow→target ) = 544.5 N
c )  If the speed was doubled:  v = 44 m/s;
F = a m
a = 6050 m/s²
a · t = 44
t = 6050 : 0.04
t = 0.007272 s
d = 44 t - 44 t/2 = 22 t
d = 22 · 0.007272
d = 0.16 m = 16 cm
8 0
3 years ago
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