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3 years ago

I’m still lost on this please help me on this I know it’s not D I got it wrong

Physics

1 answer:

RSB [31]3 years ago

5 0

Before you even look at the questions, look over the graph, so you know what kind of information is there.

The x-axis is "time". OK. You know that as the graph moves from left to right, it shows what's happening as time goes on.

The y-axis is "speed" of something. OK. When the graph is high, the thing is moving fast. When the graph is low, the thing is moving slow. When the graph slopes up, the thing is gaining speed. When the graph slopes down, the thing is slowing down. When the graph is flat, the speed isn't changing, so the thing is moving at a constant speed.

NOW you can look at the questions.

OMG ! It's only ONE question: What's happening from 'c' to 'd' ? Well I don't know. Perhaps we can figure it out if we LOOK AT THE GRAPH !

-- Between c and d, the graph is flat. The speed is not changing. It's the same speed at d as it was back at c .

What speed is it ?

-- Look back at the y-axis. The speed at the height of c and d is 'zero' .

-- The 2nd and 4th choices are both correct. From c to d, the speed is constant. The constant speed is zero. The car is not moving.

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3 years ago

Three cars (car F, car G, and car H) are moving with the same speed and slam on their brakes. The most massive car is car F, and

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To solve this problem it is necessary to apply the concepts related to Normal Force, frictional force, kinematic equations of motion and Newton's second law.

From the kinematic equations of motion we know that the relationship of acceleration, velocity and distance is given by

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Where,

$v_f =$ Final velocity

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a = Acceleration

x = Displacement

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$F_f = \mu_k (mg) \rightarrow$ Frictional Force

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Where,

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g = Gravity

Equating both equation we have that

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Therefore,

$v_f^2=v_i^2+2ax$

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Re-arrange to find x,

$x = \frac{v_i^2}{2(-\mu_k g)}$

The distance traveled by the car depends on the coefficient of kinetic friction, acceleration due to gravity and initial velocity, therefore the three cars will stop at the same distance.

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2 years ago

What is the kinetic energy of a 478 kg object that is moving with the speed of 15 m/s

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3 years ago

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Answer:

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