A block (mass 9.0 kg) is released from rest on a frictionless slope angled at 37° to the horizontal. Draw a diagram with labelle
d vectors for forces/acceleration. What is the block's acceleration?
1 answer:
Answer:
Force diagram is attached here.
Acceleration of the mass down the inclined plane is independent of its mass.
ma = mg sin 37
or Acceleration = a = g sin 37 = 5.9 m/s/s.
Explanation:
The object sliding down the inclined plane has several forces acting on it.
Forces are labelled here as 1, 2, 3, 4.
Force 1 = Normal force that acts at right angles to the inclined surface.
Force 2 : Parallel component of the gravitational force
= mg sin 37.
Force 3: Mass x Acceleration due to gravity = Weight
This is the gravity force that acts perpendicular to the
floor or ground.
Force 4 : Perpendicular component of the gravitational force = mg cos 37.
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Answer:
The answer is ""
Explanation:
Answer:
The x-component of is 56.148 newtons.
Explanation:
From 1st and 2nd Newton's Law we know that a system is at rest when net acceleration is zero. Then, the vectorial sum of the three forces must be equal to zero. That is:
(1)
Where:
,
,
- External forces exerted on the ring, measured in newtons.
- Vector zero, measured in newtons.
If we know that ,
,
and
, then we construct the following system of linear equations:
(2)
(3)
The solution of this system is:
,
The x-component of is 56.148 newtons.