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algol [13]
4 years ago
6

A block (mass 9.0 kg) is released from rest on a frictionless slope angled at 37° to the horizontal. Draw a diagram with labelle

d vectors for forces/acceleration. What is the block's acceleration?

Physics
1 answer:
maxonik [38]4 years ago
7 0

Answer:

Force diagram is attached here.

Acceleration of the mass down the inclined plane is independent of its mass.

ma = mg sin 37

or Acceleration = a = g sin 37 = 5.9 m/s/s.

Explanation:

The object sliding down the inclined plane has several forces acting on it.

Forces are labelled here as 1, 2, 3, 4.

Force 1 = Normal force that acts at right angles to the inclined surface.

Force 2 : Parallel component of the gravitational force

                = mg sin 37.

Force 3: Mass x Acceleration due to gravity = Weight

This is the gravity force that acts perpendicular to the  

floor or ground.  

Force 4 : Perpendicular component of the gravitational force  = mg cos 37.  

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A 2 N and an 8 N force pull on an object to the right and a 4 N force pulls on the same object to the left. If the object has a
Elden [556K]

Answer:

a = 12 [m/s²]

Explanation:

To solve this problem we must use Newton's second law which tells us that the sum of forces on a body is equal to the product of mass by acceleration.

ΣF = m*a

where:

ΣF = sum of forces acting on a body [N] (units of Newtons)

m = mass = 0.5 [kg]

a = acceleration [m/s²]

Let's take the direction of positive forces to the right and negative forces directed to the left

2 + 8 - 4 = 0.5*a

6 = 0.5*a

a = 12 [m/s²]

7 0
3 years ago
A focal arrangement that has a thin lens that the light passes through before traveling down the tube to the objective mirror is
erica [24]
The correct answer for the question that is being presented above is this one: "Schmidt-Cassegrain focus." A focal arrangement that has a thin lens that the light passes through before traveling down the tube to the objective mirror is a Schmidt-Cassegrain focus.
Here are the following choices: 
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b. Newtonian focus
c. Schmidt-Cassegrain focus
<span>d. Schmidt focus</span>
4 0
3 years ago
A cup of water is warmed from 21 °C to 85 °C. What is the difference between these two temperatures, in kelvins?
Ilya [14]

Answer:

337k

Explanation:

First, let us find the difference between the given two temperatures.

Difference = 85°C - 21°C

                  = 64°C

<u>And now we have to write the temperature in kelvins.</u>

To convert Celcius to Kelvins you can add 273 to the temperature in Celcius.

<u>Let us find it now.</u>

64°C + 273 = 337k

Therefore,

64°C ⇒ <u>337k</u>

8 0
2 years ago
In a physics lab, light with a wavelength of 530 nm travels in air from a laser to a photocell in a time of 16.7 ns . When a sla
Harlamova29_29 [7]

Answer:

\lambda'=78.086\ nm

Explanation:

Given:

  • wavelength of light in the air, \lambda=530\times 10^{-9}\ m
  • time taken to travel from the source to the photocell via air, t=16.7\ s
  • time taken to reach the photocell via air and glass slab, t'=21.3\times 10^{-9}\ s
  • thickness of the glass slab, x=0.87\ m

<u>Now we have the relation for time:</u>

\rm time=\frac{distance}{speed}

hence,

t=\frac{d}{c}

c= speed of light in air

16.7\times 10^{-9}=\frac{d}{3\times 10^8}

d=16.7\times 10^{-9}\times 3\times 10^8

d=5.01\ m

For the case when glass slab is inserted between the path of light:

\frac{(d-x)}{c} +\frac{x}{v} =t' (since light travel with the speed c only in the air)

here:

v = speed of light in the glass

\frac{(5.01-0.87)}{3\times 10^8} +\frac{0.87}{v} =21.3\times 10^{-9}

v=4.42\times 10^7\ m.s^{-1}

Using Snell's law:

\frac{\lambda}{\lambda'} =\frac{c}{v}

\frac{530}{\lambda'} =\frac{3\times 10^8}{4.42\times 10^7}

\lambda'=78.086\ nm

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