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OleMash [197]
2 years ago
6

Does a greater amount of force always result in a greater amount of work? Why or why not? Does moving an object a greater amount

of distance always require a greater amount of work?
Physics
1 answer:
Zina [86]2 years ago
5 0
Thank you for posting your question here at brainly. I would say yes to the above question. <span>Work done is the force applied multiplied by the distance travelled. </span><span>Wd = F x d. </span><span>So if d increases, Wd increases also. I hope the answer will help you. </span>
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How are coal types classified?
rosijanka [135]
It’s carbon and it’s heat value
7 0
3 years ago
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From the top of the engineering building, you throw a ball vertically upward. the ball strikes the ground 4.00 s later. the engi
anastassius [24]
Equations of the vertical launch:

Vf = Vo - gt

y = yo + Vo*t - gt^2 / 2

Here yo = 35.0m
Vo is unknown
y final = 0
t = 4.00 s
and I will approximate g to 10m/s^2

=> 0 = 35.0 + Vo * 4 - 5 * (4.00)^2 => Vo = [-35 + 5*16] / 4 = - 45 / 4 = -11.25 m/s

The negative sign is due to the fact that the initial velocity is upwards and we assumed that the direction downwards was positive when used g = 10m/s^2.

Answer: 11.25 m/s


5 0
3 years ago
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If the equation of an average velocity of a sport car was given by the equation V(t) = 3t^2 -6t +24. Determine its displacement
alisha [4.7K]

Answer:

72

Explanation:

The displacement of an object can be found from the velocity of the object by integrating the expression for the velocity.

In this problem, the velocity of the sport car is given by the expression

v(t)=3t^2-6t+24

In order to find the expression for the position of the car, we integrate this expression. We find:

x(t)=\int v(t) dt=t^3-3t^2+24t+C

where C is an arbitrary constant.

Here we want to find the displacement after 3 seconds. The position at t = 0 is

x(0)=0^3-0+0+C=C

While the position after t = 3 s is

x(3)=3^3-3(3)^2+24(3)+C=72+C

Therefore, the displacement of the car in 3 seconds is

d=x(3)-x(0)=72+C-C=72

7 0
3 years ago
A current I flows down a wire of radius a.
Helga [31]

Answer:

(a) K = \frac{I}{2\pi a}

(b) J = \frac{I}{2\pi as}

Explanation:

(a) The surface current density of a conductor is the current flowing per unit length of the conductor.

                                   K = \frac{dI}{dL}

Considering a wire, the current is uniformly distributed over the circumferenece of the wire.

                                   dL = 2\pi r

The radius of the wire = a

                                    dL = 2\pi a

The surface current density K = \frac{I}{2\pi a}

(b) The current density is inversely proportional

                                     J \alpha  s^{-1}    

                                     J = \frac{k}{s}           ......(1)

k is the constant of proportionality

                                     I = \int\limits {J} \, dS

                                     I = J \int\limits \, dS     ........(2)

substituting (1) into (2)

                                     I = \frac{k}{s} \int\limits\, dS

                                     I = k \int\limits^a_0 \frac{1}{s}  {s} \, dS

                                     I = 2\pi k\int\limits\, dS

                                     I = 2\pi ka

                                     k = \frac{I}{2\pi a}

substitute J = \frac{k}{s}

                                     J = \frac{I}{2\pi as}

7 0
2 years ago
A sinusoidal wave has period 0.20 s and wavelength 2.0 m. What is the wave speed?
il63 [147K]

Answer:10m/s

Explanation:

Wave speed ,v=for

Where π= wavelength=2m

Period =1/f f=frequency of wave

F=1/period

=1/0.2=5Hz

So speed of waves,v=5×2=10m/s

5 0
3 years ago
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