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Answer:
Decreases.
Explanation:
Electric potential energy is the potential energy which is associated with the configuration of points charge in a system and it is the result of conservative coulomb force.
When the negatively charge ion is at the position of the negative probe than its potential energy is positive when it is move towards the positive probe it's potential energy becomes negative due to the negative ion.
Therefore, potential energy is decreases when negative charge ion moves through the water from negative probe to positive probe.
Answer:
contaminated drinking water
deaths of sea creatures that are used as a food source
limits to potential economic activities such as a fishing
Explanation:
A watershed is a large area that comprises of drainage area of all the surrounding water bodies meeting at a common affluence point before draining into sea or ocean or any other large water body. Pollution in this area can pollute the small water streams flowing through it, thereby polluting the larger water body into which it drains.
Thus, the water extracted for drinking from such area will be contaminated. Pollution in larger water body can cause death of water creature and hence pose a threat to fishing.
Answer:
The necessary separation between the two parallel plates is 0.104 mm
Explanation:
Given;
length of each side of the square plate, L = 6.5 cm = 0.065 m
charge on each plate, Q = 12.5 nC
potential difference across the plates, V = 34.8 V
Potential difference across parallel plates is given as;
![V = \frac{Qd}{L^2 \epsilon_o} \\\\d = \frac{V L^2 \epsilon_o}{Q}](https://tex.z-dn.net/?f=V%20%3D%20%5Cfrac%7BQd%7D%7BL%5E2%20%5Cepsilon_o%7D%20%5C%5C%5C%5Cd%20%3D%20%5Cfrac%7BV%20L%5E2%20%5Cepsilon_o%7D%7BQ%7D)
Where;
d is the separation or distance between the two parallel plates;
![d = \frac{VL^2 \epsilon_o}{Q} \\\\d = \frac{34.8*(0.065)^2 *8.854*10^{-12}}{12.5*10^{-9}} \\\\d = 0.000104 \ m\\\\d = 0.104 \ mm](https://tex.z-dn.net/?f=d%20%3D%20%5Cfrac%7BVL%5E2%20%5Cepsilon_o%7D%7BQ%7D%20%5C%5C%5C%5Cd%20%3D%20%20%5Cfrac%7B34.8%2A%280.065%29%5E2%20%2A8.854%2A10%5E%7B-12%7D%7D%7B12.5%2A10%5E%7B-9%7D%7D%20%5C%5C%5C%5Cd%20%3D%200.000104%20%5C%20m%5C%5C%5C%5Cd%20%3D%200.104%20%5C%20mm)
Therefore, the necessary separation between the two parallel plates is 0.104 mm